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kenny6666 [7]
3 years ago
13

What’s the relationship between the number $4 lunches you buy with $100 school lunch card and the money remaining on the card

Mathematics
1 answer:
kykrilka [37]3 years ago
8 0
You can use it 25 times 4 times 25 is 100 100 by 25 is 4
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The Fall Festival charges $0.75 per ticket for the rides. Kendall bought 18 tickets for rides and spent a total of $33.50 at the
PIT_PIT [208]

Tickets cost $0.75t. Kendall bought 18 tickets, so you can substitute 18 for the variable t because it stands for the amount of tickets bought.

$0.75(18) = $13.50

Kendall spent a total of $33.50, so that means she spent $13.50 on tickets and the rest she spent on admission, so 33.50 - 13.50 = 20; she spent $20.00 on admission.

(a) The variable are t, amount of tickets bought, and a, admission price.

(b) The linear equation for anyone who only pays for festival admission and rides would look like: 0.75t + a.

(c) I made the linear equation 0.75t + a because first you would have to pay the admission fee (a), and then you would pay for EACH ticket (t). So t would be the changing variable depending on how many tickets a person would choose to buy.

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3 years ago
Line CD contains A (4,6) and B (-2,6). The slope of the line CD is?
omeli [17]
The answer is zero because the line is completely horizontal
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Help me with this please. And kid please leave me alone cuz I didn't take your points ._.
weeeeeb [17]

Answer:

step 3 addition: 20 + 9 = 29

step 4 subtraction: 29 - 2 = 27

solution 27

Step-by-step explanation:

since there's no more multiplication or division, you add and subtract from left to right

8 0
3 years ago
IF the equation y = 2x + 1 were graphed on the given xy plane, where would the two lines intersect?
Greeley [361]
(0,1) (-0.5,0) i used desmos graphing calculator
5 0
3 years ago
at which values of x does the graph of f(x)=x^2-x-2/(x^2-1)(x^2-16) have a vertical asymptope? check all that apply
katen-ka-za [31]

Answer:

x = -4, 1, 4

Step-by-step explanation:

The function is given as:

f(x) = (x² - x -2)/[(x² - 1)(x² -16)]

We want to find the values of x where the graph will have vertical assymptote.

Vertical asymptotes are defined as vertical lines which correspond to the values of x that will make the denominator of a rational function to be zero.

Thus, to get the values of x that we will have vertical assymptotes, we have to equate the denominator to zero.

We have;

[(x² - 1)(x² -16)] = 0

Thus,

x² - 1 = 0

Or

x² - 16 = 0

So;

x² = 1

x = √1

x = 1

Or

x² = 16

x = ±√16

x = ±4

Values of x that give vertical assymptote are;

x = -4, 1, 4

3 0
3 years ago
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