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slavikrds [6]
3 years ago
10

Please help 10 point reward​

Mathematics
1 answer:
LekaFEV [45]3 years ago
4 0

ANSWER:    I can give you the steps to figure out this question.

1  if it is starting at the 6 on the y axis, then just do up 1 over 1 until you get to the 10

The answer to your question is..... 6y+1=4x+10

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What is 3 1/5-1 3/10=p+5/6?
DENIUS [597]
3\frac{1}{5}-1\frac{3}{10}=p+\frac{5}{6}\\\\3\frac{2}{10}-1\frac{3}{10}-\frac{5}{6}=p\\\\p=2\frac{12}{10}-1\frac{3}{10}-\frac{5}{6}\\\\p=1\frac{9}{10}-\frac{5}{6}\\\\p=1\frac{27}{30}-\frac{25}{30}\\\\p=1\frac{2}{30}\\\\p=1\frac{1}{15}
6 0
3 years ago
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Can u help me with (29,30,31)
Gennadij [26K]

Answer:

v = -5, t = -13. , d = -12

Step-by-step explanation:

29) 3v - 9v = 30

Simplifying gives us -6v = 30. Then dividing both sides by -6 reaches our answer of v = -5.

30)12t - 8t = -52

Simplifying gives us 4t = -52. We can divide both sides by 4 to reach a conclusion that t = -13.

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3 0
3 years ago
If the acceleration of an object is given by dv/dt = −2v, Find the position function s(t) if v(0) = 7 and s(0) = 0.
kirill [66]

Answer:

Step-by-step explanation:

Given that acceleration of an object is

\frac{dv}{dt} =-2v\\\frac{dv}{v} =-2dt\\ln v = -2t+C\\

is the solution to the differential equation

Since v(0) =7

we get ln 7 = C

Hence lnv = -2t+ln 7\\v=7e^{-2t}

since velocity is rate of change of distance s we have

v=\frac{ds}{dt} =7e^{-2t}\\s= [tex]s(t) =\frac{-7}{2} (e^{-2t})+C)[

substitute t=0 and s=0

C=7/2

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Answer:

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Step-by-step explanation:

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