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Likurg_2 [28]
3 years ago
6

Relations expressed as ordered pairs are?

Mathematics
1 answer:
romanna [79]3 years ago
5 0
The relations are domain and range
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A bank security camera is mounted on a wall. The camera is set at an angle of depression of 19 degrees so that it is focused on
777dan777 [17]

Answer:

8.95feet

Step-by-step explanation:

The set up is a right angled triangle where;

The camera's horizontal distance from the focus point = 26feet = Adjacent;

The height of the camera above the floor = Opposite = x

Angle of elevation = 19°

According to TOA in trig identity;

Tan theta = opp/adj

Tan 19 = x/26

x = 26tan 19

x = 26(0.3443)

X = 8.95feet

Hence the camera is placed at a height of 8.95feet above the floor

7 0
3 years ago
What is the margin of error for a sample statistic for a population with a standard deviation of 7.75?
3241004551 [841]

Answer:

Margin of Error  = 1.96 \times 7.75 = 15.19

Step-by-step explanation:

i) Margin of Error of a population with a standard deviation of 7.75?

ii) Let us assume a two tailed test with a 95% confidence interval

iii) Z_{\frac{\alpha }{2} }  = Z_{\frac{\ 0.05 }{2} } = Z_{0.025} = 1.96

iv) therefore Margin of Error  = 1.96 \times 7.75 = 15.19

6 0
3 years ago
What is 24% of 315<br> Math
ra1l [238]

Answer:

Step-by-step explanation:

24% of 315

= 24/100 × 315

= 0.24. × 315

= 75.6

6 0
3 years ago
Content attribution
Leto [7]

Answer:

12 and 6

Step-by-step explanation:

12 x 6=72

7 0
3 years ago
the Vertices of a hyperbola are at (-5, -2) and (-5, 12) and the point (-5, 30) is one of its foci. What is the equation of its
SpyIntel [72]
With the provided vertices and the focus point, the hyperbola will look like the one in the picture below.

notice the "c" distance from the center to the focus point.

since it's a vertical hyperbola, the positive fraction will be the one with the "y" in it, its center is clearly half-way between the vertices at -5, 5.

its major axis or traverse axis goes from -2 up to 12, so is 14 units long, therefore the "a" component is half that, or 7.

\bf \textit{hyperbolas, vertical traverse axis }&#10;\\\\&#10;\cfrac{(y- k)^2}{ a^2}-\cfrac{(x- h)^2}{ b^2}=1&#10;\qquad &#10;\begin{cases}&#10;center\ ( h, k)\\&#10;vertices\ ( h,  k\pm a)\\&#10;c=\textit{distance from}\\&#10;\qquad \textit{center to foci}\\&#10;\qquad \sqrt{ a ^2 + b ^2}&#10;\end{cases}\\\\&#10;-------------------------------

\bf \begin{cases}&#10;h=-5\\&#10;k=5\\&#10;a=7\\&#10;c=25&#10;\end{cases}\implies \cfrac{(y-5)^2}{7^2}-\cfrac{[x-(-5)]^2}{b}=1&#10;\\\\\\&#10;\cfrac{(y-5)^2}{7^2}-\cfrac{(x+5)^2}{b}=1\\\\&#10;-------------------------------\\\\&#10;c^2=a^2+b^2\implies \sqrt{c^2-a^2}=b\implies \sqrt{25^2-7^2}=b&#10;\\\\\\&#10;\sqrt{625-49}=b\implies \sqrt{576}=b\implies 24=b\\\\&#10;-------------------------------\\\\&#10;\cfrac{(y-5)^2}{7^2}-\cfrac{(x+5)^2}{24^2}=1\implies \cfrac{(y-5)^2}{49}-\cfrac{(x+5)^2}{576}=1

8 0
3 years ago
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