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3 years ago

Verifying Trig Functions

Mathematics

1 answer:

anzhelika [568]3 years ago

5 0

Answer:

The answer to your question is below

Step-by-step explanation:

csc α - cot α = $\frac{sin \alpha }{1 + cos \alpha }$

Work with the left part

$\frac{1}{sin\alpha } - \frac{cos \alpha }{sin \alpha}$

Simplify

$\frac{1 - cos\alpha }{sin\alpha }$

Multiply by the reciprocal

$\frac{1 - cos\alpha }{sin \alpha } x \frac{1 + cos\alpha }{1 + cos\alpha }$

Simplify

$\frac{1 - cos^{2}\alpha}{sin\alpha (1 + cos\alpha)}$

Remember that

sin²α = 1 -cos²α

Substitute the previous equation

$\frac{sin^{2}\alpha }{sin\alpha(1 + cos\alpha ) }$

Simplify

$\frac{sin\alpha}{1 + cos \alpha}$

The identity i proved.

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Which of these points are on a line that has a slope of -3?

Ira Lisetskai [31]

Simple....

using the formula $\frac{ y_{1}- y_{2} }{ x_{1}- x_{2} }$ to find slope....

1.) (9,2)(4,3)

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3 years ago

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Answer:

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3 years ago

Identify the relationship then solve for x

kupik [55]

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3 years ago

The lengths of two sides of a triangle are 10 and 24, and the third side is x. How many whole number values are possible for x.

solong [7]

Answer:

$20$ .

Step-by-step explanation:

In any triangle, the sum of the lengths of any two sides should be strictly greater than the length of the third side. For example, if the length of the three sides are $a$ , $b$ , and $c$ :

$a + b > c$ ,

$a + c > b$ , and

$b + c > a$ .

In this question, the length of the sides are $10$ , $24$ , and $x$ . The length of these sides should satisfty the following inequalities:

$10 + 24 > x$ ,

$10 + x > 24$ , and

$24 + x > 10$ .

Since $x > 0$ , the inequality $24 + x > 10$ is guarenteed to be satisfied.

Simplify $10 + 24 > x$ to obtain the inequality $x < 35$ .

Similarly, simplify $10 + x > 24$ to obtain the inequality $x > 14$ .

Since $x$ needs to be a whole number, the greatest $x$ that satisfies $x < 35$ would be $34$ . Similarly, the least $x\!$ that satisfies $x > 14$ would be $15$ . Thus, $x\!\!$ could be any whole number between $15\!$ and $34\!$ (inclusive.)

There are a total of $34 - 15 + 1 = 20$ distinct whole numbers between $15$ and $34$ (inclusive.) Thus, the number of possible whole number values for $x$ would be $20$ .

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3 years ago

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