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Andrei [34K]
3 years ago
12

WILL GIVE BRAINLIEST Plz help me.... : /

Mathematics
2 answers:
il63 [147K]3 years ago
8 0
-7,3. if you use slide and divide
andreyandreev [35.5K]3 years ago
6 0

Answer:

(-7 , 3)

Step-by-step explanation:

3x^2 + 12x = 63 //Subtract 63 on both sides.

3x^2 + 12x - 63 = 0 //Common factor 3.

3(x^2 + 4x - 21) = 0 //Divide both sides by 3.

(x^2 + 7x - 3x - 21) = 0

x(x + 7) - 3(x + 7) = 0

(x + 7) (x - 3) = 0

x = -7 and 3

Solution: (-7, 3)

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In the illustration below, the three cube-shaped tanks are identical. The spheres in any given tank
fredd [130]

Answer:

1) Volume occupied by the spheres are equal therefore the three tanks contains the same volume of water

2) Amount \ of \, water \ remaining \ in \, the \ tank \ is \  \frac{x^3(6-\pi) }{6}

Step-by-step explanation:

1) Here we have;

First tank A

Volume of tank = x³

The  volume of the sphere = \frac{4}{3} \pi r^3

However, the diameter of the sphere = x therefore;

r = x/2 and the volume of the sphere is thus;

volume of the sphere = \frac{4}{3} \pi \frac{x^3}{8}= \frac{1}{6} \pi x^3

For tank B

Volume of tank = x³

The  volume of the spheres = 8 \times \frac{4}{3} \pi r^3

However, the diameter of the spheres 2·D = x therefore;

r = x/4 and the volume of the sphere is thus;

volume of the spheres = 8 \times \frac{4}{3} \pi (\frac{x}{4})^3= \frac{x^3 \times \pi }{6}

For tank C

Volume of tank = x³

The  volume of the spheres = 64 \times \frac{4}{3} \pi r^3

However, the diameter of the spheres 4·D = x therefore;

r = x/8 and the volume of the sphere is thus;

volume of the spheres = 64 \times \frac{4}{3} \pi (\frac{x}{8})^3= \frac{x^3 \times \pi }{6}

Volume occupied by the spheres are equal therefore the three tanks contains the same volume of water

2) For the 4th tank, we have;

number of spheres on side of the tank, n is given thus;

n³ = 512

∴ n = ∛512 = 8

Hence we have;

Volume of tank = x³

The  volume of the spheres = 512 \times \frac{4}{3} \pi r^3

However, the diameter of the spheres 8·D = x therefore;

r = x/16 and the volume of the sphere is thus;

volume of the spheres = 512\times \frac{4}{3} \pi (\frac{x}{16})^3= \frac{x^3 \times \pi }{6}

Amount of water remaining in the tank is given by the following expression;

Amount of water remaining in the tank = Volume of tank - volume of spheres

Amount of water remaining in the tank = x^3 - \frac{x^3 \times \pi }{6} = \frac{x^3(6-\pi) }{6}

Amount \ of \ water \, remaining \, in \, the \ tank =  \frac{x^3(6-\pi) }{6}.

5 0
3 years ago
marco has 37 1/2 ounces of juice he wants to pass out samples of the juice each cup can hold 2 1/2 ounces of juice how many cups
Crank
So 37 1/2
each can hold 2 1/2 oz

how many cups can he fill

37 1/2=75/2
2 1/2=5/2

x=number of cups
x times 5/2=75/2
5/2x=75/2
multiply both sides by 2
5x=75
divide both sides by 5
x=15
he can fill 15 cups
8 0
2 years ago
Read 2 more answers
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