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The line y = x and y = -x + 4 intersect when at the point (2, 2).
Expresing y = -x + 4 in terms of x, we have x = 4 - y.
Thus, the area of the region bounded by the <span>graphs of y = x, y = −x + 4, and y = 0 is given by
![\int\limits^2_0 {(y-(4-y))} \, dy = \int\limits^2_0 {(y-4+y)} \, dy \\ \\ = \int\limits^2_0 {(2y-4)} \, dy= \left[y^2-4y\right]_0^2 =|(2)^2-4(2)| \\ \\ =|4-8|=|-4|=4](https://tex.z-dn.net/?f=%20%5Cint%5Climits%5E2_0%20%7B%28y-%284-y%29%29%7D%20%5C%2C%20dy%20%3D%20%5Cint%5Climits%5E2_0%20%7B%28y-4%2By%29%7D%20%5C%2C%20dy%20%5C%5C%20%20%5C%5C%20%3D%20%5Cint%5Climits%5E2_0%20%7B%282y-4%29%7D%20%5C%2C%20dy%3D%20%5Cleft%5By%5E2-4y%5Cright%5D_0%5E2%20%3D%7C%282%29%5E2-4%282%29%7C%20%5C%5C%20%20%5C%5C%20%3D%7C4-8%7C%3D%7C-4%7C%3D4)
Therefore, the area bounded by the lines is 4 square units.
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Expresing y = -x + 4 in terms of x, we have x = 4 - y.
Thus, the area of the region bounded by the <span>graphs of y = x, y = −x + 4, and y = 0 is given by
Therefore, the area bounded by the lines is 4 square units.
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Answer:
The second function represents an even function;
Step-by-step explanation:
A function f(x) is said to be even if f(x) = f(-x). All we need to do is replace x with -x in each equation, simplify it and assess whether the equation remains unchanged. If the equation is identical to the original one then it is said to be even. Another good example of an even function is the cosine function. Moreover, even functions have y-axis symmetry
