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alexdok [17]
3 years ago
11

Simplifying rational expressions

Mathematics
1 answer:
Sonbull [250]3 years ago
3 0
1. \frac{(c + 8)(c - 8)}{(c - 8)(c + 3)}_,_
    \frac{c + 8}{c + 3}_,_

2. \frac{n^{2} + 4n - 12}{n^{2} + 2n - 8}_,_
    \frac{n^{2} + 6n - 2n - 12}{n^{2} + 4n - 2n - 8}_,_
    \frac{n(n) + n(6) - 2(n) - 2(6)}{n(n) + n(4) - 2(n) - 2(4)}_,_
    \frac{n(n + 6) - 2(n + 6)}{n(n + 4) - 2(n + 4)}_,_
    \frac{(n - 2)(n + 6)}{(n - 2)(n + 4)}_,_
    \frac{n + 6}{n + 4}_,_

3. \frac{42x^{2}y^{3}}{28x^{3}y}_,_
    \frac{3y^{2}}{2x}_,_

4. \frac{m^{2} - 3m - 10}{m - 5}_,_
    \frac{m^{2} - 5m + 2m - 10}{m - 5}_,_
    \frac{m(m) - m(5) + 2(m) - 2(5)}{m - 5}_,_
    \frac{m(m - 5) + 2(m - 5)}{m - 5}_,_
    \frac{(m + 2)(m - 5)}{m - 5}_,_
    m + 2_,_
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Using an infinite geometric series for the repeating decimal 0.551¯¯¯¯¯¯¯¯, with ratio 11000, find integers a and b so that 0.55
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Answer:

Sum = 551/999

Where a = 551 and b = 999

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Step-by-step explanation:

Given

Decimal = 0.551

Ratio = 1/1000

By repeating the decimal, we can write;

0.551 -bar = 0.551551551.....

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= n=0 Σ∝(551/10³)(1/10³)^n

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∝

Given the ratio of 1/1000

Let r = 1/1000

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a = 551/10³

The sum is defined as follows;

a/(1-r)

Sum = 551/10³ / (1 - 1/10³)

Sum = 551/1000 ÷ 999/1000

Sum = 551/999

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