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alexdok [17]
3 years ago
11

Simplifying rational expressions

Mathematics
1 answer:
Sonbull [250]3 years ago
3 0
1. \frac{(c + 8)(c - 8)}{(c - 8)(c + 3)}_,_
    \frac{c + 8}{c + 3}_,_

2. \frac{n^{2} + 4n - 12}{n^{2} + 2n - 8}_,_
    \frac{n^{2} + 6n - 2n - 12}{n^{2} + 4n - 2n - 8}_,_
    \frac{n(n) + n(6) - 2(n) - 2(6)}{n(n) + n(4) - 2(n) - 2(4)}_,_
    \frac{n(n + 6) - 2(n + 6)}{n(n + 4) - 2(n + 4)}_,_
    \frac{(n - 2)(n + 6)}{(n - 2)(n + 4)}_,_
    \frac{n + 6}{n + 4}_,_

3. \frac{42x^{2}y^{3}}{28x^{3}y}_,_
    \frac{3y^{2}}{2x}_,_

4. \frac{m^{2} - 3m - 10}{m - 5}_,_
    \frac{m^{2} - 5m + 2m - 10}{m - 5}_,_
    \frac{m(m) - m(5) + 2(m) - 2(5)}{m - 5}_,_
    \frac{m(m - 5) + 2(m - 5)}{m - 5}_,_
    \frac{(m + 2)(m - 5)}{m - 5}_,_
    m + 2_,_
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Answer:

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Step-by-step explanation:


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Which of the following is the contrapositive of the statement "If I travel, I will go to France"?
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7 0
3 years ago
Read 2 more answers
What if this function simplified?
almond37 [142]

Hi!

Let's first expand the cotangent of theta.

You'll probably know that tangent will be "y/x", or \frac{sin(x)}{cos(x)}, and cotangent is the reciprocal of this, meaning that it is "x/y" or \frac{cos(x)}{sin(x)}.

That means that we are now given this equation.

cos(x)\frac{cos(x)}{sin(x)}+sin(x)

That'll multiply to:

\frac{cos^2(x)}{sin(x)}+sin(x)

We'll want a common denominator to add by multiplying sin(x) to both top and bottom of the second term:

\frac{cos^2(x)}{sin(x)}+\frac{sin^2(x)}{sin(x)}

\frac{cos^2(x)+sin^2(x)}{sin(x)}

Pythagorean Identity states that sin^2(x)+cos^2(x)=1, so substitute that in:

\frac{1}{sin(x)}

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7 0
3 years ago
Write 10/12 in the simplest form
maria [59]
5/6 is the simplest form. you divide 10 and 12 by 2 making 5 and 6.
8 0
4 years ago
PlEASE ANSWER FAST!!!!!!!!!!!!
muminat
<span>Diameter of a grain of sand = 2 x 10^{-4} 

</span><span>Diameter of the average cell in the human body = 1 x 10^{-5}
</span>
Difference of diameter of grain of sand and cell of human body

= 2 x 10^{-4} - 1 x 10^{-5}

= 2 * 10^{-4} - 1 * 10^{-5} = ( \frac{2* 10^{-4}}{10^{-5}} -  \frac{1*10^{-5}}{10^{-5}} )*10^{-5}

= (2*10^{-4-(-5)} - 1*10^{-5-(-5)})*10^{-5}

= (2*10^{-4+5}-1*10^{-5+5})*10^-5= (2*10^{1}-1*10^{0})*10^{-5}

= (2*10 - 1*1) *10^{-5} = (20 - 1)*10^{-5}

= 19 * 10^{-5}

= 19 × 10^{-5}

Hence, the diameter of a grain of sand is 19 × 10^{-5} longer than the diameter of the average cell of the human body.
7 0
3 years ago
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