Answer and Step-by-step explanation: The described right triangle is in the attachment.
As it is shown, AC is the hypotenuse and BC and AB are the sides, so use Pytagorean Theorem to find the unknown measure:
AC² = AB² + BC²




AB = 5.4
Then, right triangle ABC measures:
AB = 5.4cm
BC = 4.5cm
AC = 7cm
Answer:
y = -1/2x - 11/2
Step-by-step explanation:
y2 - y1 / x2 - x1
-4 - (-5) / -3 - (-1)
1/ -2
= -1/2
y = -1/2x + b
-5 = -1/2(-1) + b
-5 = 1/2 + b
-11/2 = b
Answer:
x=6
Step-by-step explanation:
The inverse is the equation with the x and y variables transposed
Answer:
Multiple answers
Step-by-step explanation:
The original urns have:
- Urn 1 = 2 red + 4 white = 6 chips
- Urn 2 = 3 red + 1 white = 4 chips
We take one chip from the first urn, so we have:
The probability of take a red one is :
(2 red from 6 chips(2/6=1/2))
For a white one is:
(4 white from 6 chips(4/6=(2/3))
Then we put this chip into the second urn:
We have two possible cases:
- First if the chip we got from the first urn was white. The urn 2 now has 3 red + 2 whites = 5 chips
- Second if the chip we got from the first urn was red. The urn two now has 4 red + 1 white = 5 chips
If we select a chip from the urn two:
- In the first case the probability of taking a white one is of:
= 40% ( 2 whites of 5 chips) - In the second case the probability of taking a white one is of:
= 20% ( 1 whites of 5 chips)
This problem is a dependent event because the final result depends of the first chip we got from the urn 1.
For the fist case we multiply :
x
=
= 26.66% (
the probability of taking a white chip from the urn 1,
the probability of taking a white chip from urn two)
For the second case we multiply:
x
=
= .06% (
the probability of taking a red chip from the urn 1,
the probability of taking a white chip from the urn two)
Answer:
170 children
74 students
85 adults
Step-by-step explanation:
Given
Let:

For the capacity, we have:

For the tickets sold, we have:

Half as many as adults are children implies that:

Required
Solve for A, C and S
The equations to solve are:
-- (1)
-- (2)
-- (3)
Make C the subject in (3)

Substitute
in (1) and (2)
-- (1)


Make S the subject

-- (2)



Substitute 



Solve for A


Recall that: 


Recall that: 



Hence, the result is:


