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3 years ago

8

Please help me with this question #11

1 answer:

Lena [83]3 years ago

3 0

The answer is A. I hope this helps!

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Solve each system by elimination

MaRussiya [10]

X-y=11
2x+y=19
add them

x-y=11
<u>2x+y=19 +</u>
3x+0y=30

3x=30
divide 3
x=10

sub baack
x-y=11
10-y=11
minus 10
-y=1
times -1
y=-1

(x,y)
(10,-1)

3 0

3 years ago

Gabe Industries sells two products, Basic models and Deluxe models. Basic models sell for $41 per unit with variable costs of

Hitman42 [59]

Answer:

b. 63 units

Step-by-step explanation:

The breakeven point occurs when the revenue is equal to the expenses. It means that the profit is 0. So, for the Basic model, the revenue is the sell less the costs: $41 - $15 = $26.For the Deluxe model, the revenue per unit is 0 ($45 - $45).

So, calling x the Basic model units, ad y the Deluxe model units, the total revenue will be: 26x, which must be equal to the expenses = $1,310.40:

26x = 1310.40

x = 50.4 units

y = x/4, because for 1 Deluxe model four Basic models are selled.

y = 50.4/4 = 12.6 units

The total units for breakeven point is 50.4 + 12.6 = 63 units.

8 0

3 years ago

I have no idea what the answer is or how to get it.

Lostsunrise [7]

I can't see the question

5 0

3 years ago

A certain college graduate borrows 7864 dollars to buy a car. The lender charges interest at an annual rate of 13%. Assuming tha

White raven [17]

Answer:

Therefore rate of payment = $ 3145.72

Therefore the rate of interest = =$1573.17

Step-by-step explanation:

Consider A represent the balance at time t.

A(0)=$ 7864.

r=13 % =0.13

Rate payment = $k

The balance rate increases by interest (product of interest rate and current balance) and payment rate.

$\frac{dB}{dt} = rB-k$

$\Rightarrow \frac{dB}{dt} - rB=-k$ .......(1)

To solve the equation ,we have to find out the integrating factor.

Here p(t)= the coefficient of B =-r

The integrating factor $=e^{\int p(t) dt$

$=e^{\int (-r)dt$

$=e^{-rt}$

Multiplying the integrating factor the both sides of equation (1)

$e^{-rt}\frac{dB}{dt} -e^{-rt}rB=-ke^{-rt}$

$\Rightarrow e^{-rt}dB - e^{-rt}rBdt=-ke^{-rt}dt$

Integrating both sides

$\Rightarrow \int e^{-rt}dB -\int e^{-rt}rBdt=\int-ke^{-rt}dt$

$\Rightarrow e^{-rt}B=\frac{-ke^{-rt}}{-r} +C$ [ where C arbitrary constant]

$\Rightarrow B(t)=\frac{k}{r} +Ce^{rt}$

Initial condition B=7864 when t =0

$\therefore 7864= \frac{k}{r} - Ce^0$

$\Rightarrow C= \frac{k}{r} -7864$

Then the general solution is

$B(t)=\frac{k}{r}-( \frac{k}{r}-7864)e^{rt}$

To determine the payment rate, we have to put the value of B(3), r and t in the general solution.

Here B(3)=0, r=0.13 and t=3

$B(3)=0=\frac{k}{0.13}-( \frac{k}{0.13}-7864)e^{0.13\times 3}$

$\Rightarrow- 0.48\frac{k}{0.13} +11614.98=0$

⇒k≈3145.72

Therefore rate of payment = $ 3145.72

Therefore the rate of interest = ${(3145.72×3)-7864}

=$1573.17

4 0

3 years ago

Write 5 + = 6 + 8. write a number to make the sentence true. draw a quick picture to explain.

mel-nik [20]

9 would be answer. when you plug in the 9 to the equation you get 14=14 which is a true statement.

8 0

3 years ago