David bought a poster for an art project. The poster is 2.7 ft wide and 3.9 ft tall. What is the area of the poster? Enter your

Question

2 years ago

8

answer as a DECIMAL in the box.

2 answers:

Anarel [89] · Answer 1 · 2022-05-28T11:39:30+03:00

5 0

10.53 is the answer. Just multiply the two numbers.

Nadusha1986 [10] · Answer 2 · 2022-05-28T12:45:37+03:00

Answer: The area of the poster is 10.53 sq. ft.

Step-by-step explanation: Given that the poster that David bought for an art project is 2.7 ft wide and 3.9 ft tall.

We are to find the area of the poster.

A picture of the poster ABCD is shown in the attached figure. The poster is always in the form of a rectangle with length as its height.

Given,

length of the poster, l = BC = 3.9 ft,

and

width of the poster, w, CD = 2.7 ft.

Therefore, the area of the poster will be

$A=BC \times CD=l\times w=3.9\times 2.7=10.53~\textup{sq. ft.}$

Thus, the area of the poster is 10.53 sq. ft.