The hyperbolic cos (cosh) is given by
cosh (x) = (e^x + e^-x) / 2
The slope of a tangent line to a function at a point is given by the derivative of that function at that point.
d/dx [cosh(x)] = d/dx[(e^x + e^-x) / 2] = (e^x - e^-x) / 2 = sinh(x)
Given that the slope is 2, thus
sinh(x) = 2
x = sinh^-1 (2) = 1.444
Therefore, the curve of y = cosh(x) has a slope of 2 at point x = 1.44
Answer:
4 number
Step-by-step explanation:
16p+32q=1,280
Answer:
fraction 4/12 or 1/3
decimal .333333333
percent 33%.333333
Step-by-step explanation:
Answer:
In order of pictures,
Picture #1: 230
Picture #2: 140
Picture #3: 9.9
Picture #4: 13.5
Picture #5: 7.07
Step-by-step explanation:
I am not entirely sure that 3 - 5 are correct, but I know that 1 and 2 are correct. I am sorry if they are incorrect.
Hope that this helps!
