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cupoosta [38]
3 years ago
8

Tell whether (-2,3)is a solution of 2y+x=4?

Mathematics
2 answers:
poizon [28]3 years ago
5 0

Answer:

Yes, it is a solution

Step-by-step explanation:

That is because if you put x=-2 and y=3 in the equation you will get 2*3+(-2)=4 therefore 6-2=4 which equals to 4=4

IRINA_888 [86]3 years ago
3 0

Answer:

Yes

Step-by-step explanation:

2y + x = 2 * 3 + (-2) =  6-2 = 4 which is equal to the R.H.S (right hand side)

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Answer:

We know that the equation of the circle in standard form is equal to <em>(x-h)² + (y-k)² = r²</em> where (h,k) is the center of the circle and r is the radius of the circle.

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1 - We first group terms with the same variable :

(x²+8x) + (y²+22y) + 37 = 0

2 - We then move the constant to the opposite side of the equation (don't forget to change the sign !)

(x²+8x) + (y²+22y) = - 37

3 - Do you recall the quadratic identities ? (a+b)² = a² + 2ab + b². Now that's what we are trying to find. We call this process <u><em>"completing the square"</em></u>.

x²+8x = (x²+8x + 4²) - 4² = (x+4)² - 4²

y²+22y = (y²+22y+11²)-11² = (y+11)²-11²

4 - We plug the new values inside our equation :

(x+4)² - 4² + (y+22)² - 11² = -37

(x+4)² + (y+22)² = -37+4²+11²

(x+4)²+(y+22)² = 100

5 - We re-write in standard form :

(x-(-4)²)² + (y - (-22))² = 10²

And now it is easy to identify h and k, h = -4 and k = - 22 and the radius r equal 10. You can now complete the sentence :)

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