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julsineya [31]
3 years ago
7

A camp tent has a center pole 8feet high. The sides of the tent make an angle of 40° degrees with the ground how wide is the ten

t
Mathematics
1 answer:
kati45 [8]3 years ago
8 0

Answer:

Step-by-step explanation:

let the distance from central pole to one end=r

8/r=tan 40°

r=8/tan40=8 cot~40°=8 cot(90-50)=8 tan ~50≈9.534

2r≈19.068≈ 19.1

width of tent=19.1 ft

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mario62 [17]
The answer is B) Translation, Congruent
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3 years ago
A+9 write this in a verbal expression
balandron [24]

Nine more than a variable "a".

7 0
3 years ago
What’s the answer to this question
laiz [17]

Answer:

B

Step-by-step explanation:

3 rectangles are 3 x 7 x 2 = 42

2 triangles are 2 x 1/2 x 2 x \sqrt{2^{2} - 1^{2}   } = 2\sqrt{3}

note that you have to use Pythagoras Theorem to solve for the height of the triangle

4 0
3 years ago
Rita started the day with r apps then she deleted 5 apps and still had twice as many apps as Cora has .write and an equation tha
Elodia [21]

Answer:

r - 5 = 2c

r = 75

Step-by-step explanation:

To write an equation for the problem, we first need do declare the value of the number of apps cora has.

Let c = Cora's apps

r - 5 = 2c

r - 5 is used to indicate that Rita deleted 5 apps.

2c is used to represent the twice the number of apps Cora has.

Now you said that Cora had 35 apps.

Let's plug that into the equation.

r - 5 = 2c

r - 5 = 2(35)

r - 5 = 70

Now we transpose the -5 to the other side to leave r.

r = 70 + 5

r = 75

So if Cora has 35 apps, then Rita will have 75 apps.

3 0
3 years ago
Need help please help me
Ostrovityanka [42]
The solution is the point of intersection between the two equations.

Assuming you have a graphing calculator or a program to lets you graph equations (I use desmos) you simply put in the equetions and note down the coordinates of the point of intersection.

In the graph the first equation is in blue and the second in red.

The point of intersection = the solution = (-6 , -1)



If you dont have access to a graphing calculator you could draw the graphs by hand;

1) Draw a table of values for each equation; you do this by setting three or four values for x and calculating its image in y (you can use any values of x)

y = 0.5 x + 2 (Im writing 0.5 instead of 1/2 because I find its easier in this format)

x | y
-1 | 1.5 * y = 0.5 (-1) + 2 = 1.5
0 | 2 * y = 0.5 (0) + 2 = 2
1 | 2.5 * y = 0.5 (1) + 2 = 2.5
2 | 3 * y = 0.5 (2) + 2 = 3

y = x + 5

x | y
-1 | 4 * y = (-1) + 5 = 4
0 | 5 * y = (0) + 5 = 5
1 | 6 * y = (1) + 5 = 6
2 | 7 * y = (2) + 5 = 7

2) Plot these point on the graph
I suggest to use diffrent colored points or diffrent kinds of point markers (an x or a dot) to avoid confusion about which point belongs to which graph

3) Using a ruler draw a line connection all the dots of one graph and do the same for the other

4) The point of intersection is the solution

8 0
4 years ago
Read 2 more answers
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