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Sav [38]
2 years ago
14

Graph the result of the following transformation on f(x)​

Mathematics
1 answer:
pshichka [43]2 years ago
7 0

The graph would be the normal parent function of f(x) but all points would be 6 units up.

There's an upward vertical shift of 6. To graph this, you need to graph the function f(x) and then add 6 units to all the y values.

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What is the equation of the line that passes through the point (–5,–6) and has a slope of zero?
Lorico [155]

Answer:

y = -6

Step-by-step explanation:

y = mx +  b

-6 = -5(0) + b

b = -6

5 0
3 years ago
Part A
Nat2105 [25]

Answer:

A.  f(n) =0.2n+4.8

B. The y intercept is 4.8

Step-by-step explanation:

Given

a_n= 5 + 0.2(n-1)

Solving (a): Write as a function.

To do this, we simply substitute f(n) for a_n

a_n= 5 + 0.2(n-1) becomes

f(n)= 5 + 0.2(n-1)

Open Bracket

f(n) = 5 + 0.2n-0.2

Collect Like Terms

f(n) =0.2n-0.2 + 5

f(n) =0.2n+4.8

B. The y intercept.

To get the y intercept, we set n to 0

i.e

f(0) =0.2 * 0+4.8

f(0) =0+4.8

f(0) =4.8

Hence, the y intercept is 4.8

4 0
2 years ago
How many times does 5 go in to 47
Feliz [49]
47/5=9.40
9*5=45
47/5= 9 2/5
6 0
3 years ago
Find the value of the expressions 3x^3-2y^3-6x^2y^2+xy for x=2/3 and y=1/2
fiasKO [112]

Hi!

3x^3-2y^3-6x^2y^2+xy=\\\\=3\cdot(\frac{2}{3})^3-2\cdot(\frac{1}{2})^3-6\cdot(\frac{2}{3})^2\cdot(\frac{1}{2})^2+\frac{2}{3}\cdot\frac{1}{2}=\\\\=3\cdot\frac{8}{27}-2\cdot\frac{1}{8}-6\cdot\frac{4}{9}\cdot\frac{1}{4}+\frac{1}{3}=\\\\=\frac{8}{9}-\frac{1}{4}-\frac{2}{3}+\frac{1}{3}=\frac{8}{9}-\frac{1}{4}-\frac{1}{3}=\frac{32}{36}-\frac{9}{36}-\frac{12}{36}=\boxed{\frac{11}{36}}

5 0
2 years ago
Pls say hard very hard​
Simora [160]

(a) From the histogram, you can see that there are 2 students with scores between 50 and 60; 3 between 60 and 70; 7 between 70 and 80; 9 between 80 and 90; and 1 between 90 and 100. So there are a total of 2 + 3 + 7 + 9 + 1 = 22 students.

(b) This is entirely up to whoever constructed the histogram to begin with... It's ambiguous as to which of the groups contains students with a score of exactly 60 - are they placed in the 50-60 group, or in the 60-70 group?

On the other hand, if a student gets a score of 100, then they would certainly be put in the 90-100 group. So for the sake of consistency, you should probably assume that the groups are assigned as follows:

50 ≤ score ≤ 60   ==>   50-60

60 < score ≤ 70   ==>   60-70

70 < score ≤ 80   ==>   70-80

80 < score ≤ 90   ==>   80-90

90 < score ≤ 100   ==>   90-100

Then a student who scored a 60 should be added to the 50-60 category.

8 0
2 years ago
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