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vampirchik [111]
3 years ago
13

Is the sequence {an} bounded above by a number? If yes, what number? Enter a number or enter DNE. Is the sequence {an} bounded b

elow by a number? If yes, what number? Enter a number or enter DNE. Select all that apply: The sequence {an} is A. unbounded. B. bounded above. C. bounded. D. bounded below.
Mathematics
1 answer:
Mumz [18]3 years ago
5 0

Answer:

The sequence {an} is A. unbounded

Step-by-step explanation:

The sequence {an} is unbounded.

we say a sequence is bounded if and only it is bounded both above and it is also bounded below. clearly the sequence {an} is an unbounded sequence.

The sequence {an} is <u>bounded</u> if there is a number M>0 such that |an|≤M for every positive n.Every unbounded sequence is divergent

The sequence{an}. is an unbounded sequence, because it has no a finite upper bound

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3 years ago
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0.33333333333333333333333333333333333333333333333 simplified at a fraction
USPshnik [31]

Answer:

\frac{1}{3}

Step-by-step explanation:

Your original number to convert is 0.333333. Let's slide the decimal point in this number to the right 1 place(s) (the same number of digits in the number 3).

If we do this, we'll get a 3.333333 (slide the decimal in the 0.333333 right 1 places, you'll get 3.333333).

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Now, solving 9x=3 for x by dividing both sides of it by 9, we'll get that x=3/9. And this is your answer.

How is this your answer? Well remember that above, x was originally set equal to 0.333333 via x = 0.333333, and now we have that x is also equal to 3/9, so that means 0.333333 = 3/9..and there's 0.333333 written as a fraction.

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<u>Simplify 3/9 into the lowest terms:</u>

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Answer:

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Step-by-step explanation:

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