As we know y=3/4x-3
Let's put it in the second equation
3/4x-3=1/4x+1
3/4 x -1/4 x = 1+3
2/4 x = 4
X= 4*4/2
x=8
Put x= 8 in first equation
y= 3/4 *8 -3
y=6-3
y=3
Check the answer
3=3/4 *8 -3
3=6-3
3=3
Correct
So(y, x) = (3,8)
Because x=8 and y=3
Answer:
c. 2
Step-by-step explanation:
Given : X = No. of hours worked
No. of people work for the manager = 50
X = 3, 4 , 5 , 6 , 7, 8
P(X) = 0.1 , ? , 0.14 , 0.3 , 0.36 , 0.06
To Find : No. of people work for four hours
Solution : First understand the fact that sum of all probabilities is equal to 1
So, sum of all values of P(X) = 1
⇒
⇒
⇒
⇒
So, the probability of no. of people worked for 4 hours is 0.04.
⇒P(4)=0.04
Thus , To calculate no. of people work for four hours :
⇒ 2 no. of people work for four hours per shift .
Step-by-step explanation:
I am not fully sure what your teacher is aiming for. it friends very much on what you were just discussing in class (which I don't know).
but the first thing coming to mind is a minus sign ("-"). squaring a negative number removed the minus and makes the result equal to squaring the same positive number.
just for the undoing the 1/2 :
that is, because a fraction as exponent specifies in its denominator the root to be calculated for the basic value or expression.
so, 1/2 means square root. and yes, square is the inverse function of a square root, and it "undoes" the square root.
in exponent calculation it just means that for exponent 1 to the power of exponent 2 we simply multiply both exponents. and so, 1/2 × 2 = 1
FYI - the numerator still represents an original "to the power of" operation.
so, e.g. 3/2 would mean put the basis to the power of 3 and then do the square root of that result. or the other way around. these operations are commutative (the sequence does not matter).
The probability that his number will be 4 is one in eleven, or 1/11.
Answer: First option.
Step-by-step explanation:
To solve for "h" from the given the equation 
, you need to:
Apply the Subtraction property of equality and subtract 
to both sides of the equation.
Then you need to apply the Division property of equality and divide both sides of the equation by 
.
Then:
