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Hope This Helps
8
Suppose f(x) = ----------
sqrt(x)
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What if we let x = 16 (just an example)? We'd get f(16) = ------------- = 2.
sqrt(16)
What if we let x = g(x) = 2x+4?
We'd get the following:
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f(g(x)) = -------------- = y
sqrt(2x+4)
So...the correct answer is the fourth one.
Answer:
B. 8.35
Step-by-step explanation:
3.5 x 1.7 = 5.95
5.95 + 2.4 = 8.35
You multiply first because of PEMDAS.
P=parenthesis
E=exponents
M=multiply
D=divide
A=add
S=subtract
Answer:
B-2/6
Step-by-step explanation:
three will subract the one since they all have the same dinominaters where by the answer is B
d) You have a <u>difference of squares</u>:
49y² - 9 = (7y)² - 3²
Recall the identity,
a² - b² = (a - b) (a + b)
So,
49y² - 9 = (7y - 3) (7y + 3)
e) Pull out the common factor 3 from each term:
3x² - 3x - 90 = 3 (x² - x - 30)
Now use the <u>sum-product method</u>. Notice that we can write 30 = 5 • 6, and 5 - 6 = 1, so
3x² - 3x - 90 = 3 (x + 5) (x - 6)
f) Same as in (e), use the <u>sum-product method</u>. Notice that 42 = 7 • 6, and -7 - 6 = -13, so
x² - 13x + 42 = (x - 7) (x - 6)
