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SpyIntel [72]
3 years ago
7

The ability to do work is how we measure A. power B. work C. force D. joule

Mathematics
2 answers:
erastova [34]3 years ago
8 0
The answer is D. joule
Hope this helps!
Sergio [31]3 years ago
5 0
The ability to do work is known as "Power" which we measure in "Watt"

In short, Your Answer would be Option A

Hope this helps!
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Choice 1: Angela and Kellie went to lunch. Their bill before tax was $20.00. Tax is 8%. How much tax should
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Answer:

$1.60

Step-by-step explanation:

Amount of tax paid = percentage of tax to be paid x bill before tax

0.08 x $20 = $1.60

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3 years ago
The volume of most drink containers in the United States is measured in fluid ounces. There
attashe74 [19]

Answer:

68 ounces

Step-by-step explanation:

Most drink containers in the United States are usually known as 2 Litres bottle.

Now, let's convert this 2 litres to cubic centimeters.

1 litre is equal to 1000 cm³

So, 2 Litres = 2000 cm³

Since there are 29.6 cm³ per fluid ounce, thus amount of ounces held by the typical cup in america = 2000/29.6 = 67.57 ounces ≈ 68 ounces

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3 years ago
You bought a Nissan Xterra for $25,000. The car depreciates at a rate of
cestrela7 [59]

Answer:

Why i dont know

Step-by-step explanation:

4 0
3 years ago
There are 20 students at lunch. One-fifth of the student are in the hall. How many people are in the hall
SashulF [63]
There are 4 people in the hall
6 0
3 years ago
Read 2 more answers
The magic dragon cigarette company claims that their cigarettes contain an average of only 10 mg of tar. a random sample of 100
9966 [12]

Answer:

t=\frac{11.5-10}{\frac{4.5}{\sqrt{100}}}=3.333    

Critical value

The significance is 5% so then \alpha=0.05 and \alpha/2=0.025 then the critical value for this case would be z_{\alpha/2}= 1.64. Since the calculated value is higher than the critical value we have enough evidence to reject the null hypothesis and we can conclude that the true mean is higher than 10 mg

P value

The p value would be given

p_v =P(z>3.333)=0.000434  

Since the p value is lower than the significance level we have enough evidence to reject the null hypothesis and we can conclude that the true mean is significantly higher than 10 mg

Step-by-step explanation:

Information given

\bar X=11.5 represent the sample mean

\sigma=4.5 represent the population standard deviation

n=100 sample size  

\mu_o =10 represent the value that we want to test

\alpha=0.05 represent the significance level for the hypothesis test.  

t would represent the statistic

p_v represent the p value

Hypothesis to test

We want to test if the true mean is higher than 10mg, the system of hypothesis would be:  

Null hypothesis:\mu \leq 10  

Alternative hypothesis:\mu > 10  

the statistic for this case would be given by:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

Replacing we got:

t=\frac{11.5-10}{\frac{4.5}{\sqrt{100}}}=3.333    

Critical value

The significance is 5% so then \alpha=0.05 and \alpha/2=0.025 then the critical value for this case would be z_{\alpha/2}= 1.64. Since the calculated value is higher than the critical value we have enough evidence to reject the null hypothesis and we can conclude that the true mean is higher than 10 mg

P value

The p value would be given

p_v =P(z>3.333)=0.000434  

Since the p value is lower than the significance level we have enough evidence to reject the null hypothesis and we can conclude that the true mean is significantly higher than 10 mg

6 0
3 years ago
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