<span> The </span>midpoints<span> of the </span>sides<span> of the </span>triangle<span> are </span>joined<span> to </span>form another equilateral triangle<span> with </span>sides<span> that are </span>half<span> the leng ... the </span>length<span> of the </span>outer triangle<span>. This </span>process<span> is </span>continued until three triangles<span> are </span>inscribed<span> in the </span>first triangle<span>. The </span>sum<span> of the </span>perimeters<span> of </span>all four triangles<span> is how many </span>inches<span>?</span>
Circles!!!
The general formula is:
x^2 + y^2 = r^2
where x and y form the circle while r is the radius.
You already have the problem set up in its general form and you don't want the radius squared... so square root everything.
If you do that then you'll get:
x + y = 5
where 5 is the radius and NOT the radius squared. If you have questions then leave a comment. Good luck!
Answer:
4.1n
Step-by-step explanation:
Let's simplify step-by-step.
n−4.6n−3.3n+2.8n
=n+−4.6n+−3.3n+2.8n
Combine Like Terms:
=n+−4.6n+−3.3n+2.8n
=(n+−4.6n+−3.3n+2.8n)
=−4.1n
v = hvh
Simplifying the above equation:
v = h × v × h
Taking the RHS 'v' to LHS
⇒ v ÷ v = h × h
⇒ 1 = h × h
⇒ 1 = 
⇒ h = √1
⇒ h = 
So h can have the values +1 or -1.
Putting h = +1 in the equation,
v = (+1) × v × (+1)
⇒ v = v
Hence, v can take any integer value.
Putting h = -1 in the equation, when h = 1.
v = (-1) × v × (-1)
⇒ v = v
Hence, v can take any integer value when h = -1.
Hence, as long as h is either +1 or -1, v can take any integer value.
Answer:
Step-by-step explanation:
40.25 x 0.15 =
Then 40.25+ the number^ then thts your answer
