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3 years ago

11

What is the slope of a line that goes through (-5,-5) and (5,-7)

2 answers:

sineoko [7]3 years ago

6 0

The answer is a.) -1.5

vlabodo [156]3 years ago

4 0

Answer:

-1/5

Step-by-step explanation:

slope formula:

m = y₂ - y₁ / x₂ - x₁

Two points are given:

(-5, -5) (5, -7)

m = -7 - (-5) / 5 - (-5)

m = -2 / 10

m = -1/5

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1. Over the six months what was the average market price per share?

lozanna [386]

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c) Since the cost per share in June was $12, and her average cost was $10.30, dollar-cost averaging worked in her favor since her average cost was lower.

6 0

3 years ago

Find the area of a trapezium whose parallel sides are 28.7 cm and 22.3 cm and distance between parallel sides is 16 cm.

puteri [66]

Given:

The parallel sides of a trapezium are 28.7 cm and 22.3 cm.

The distance between parallel sides is 16 cm.

To find:

The area of a trapezium.

Solution:

The area of the trapezium is:

$A=\dfrac{a+b}{2}h$

Where, $a,b$ are parallel sides and $h$ is the vertical distance between the parallel sides.

Putting $a=28.7, b=22.3,h=16$ in the above formula, we get

$A=\dfrac{28.7+22.3}{2}\times(16)$

$A=\dfrac{51}{2}\times 16$

$A=51\times 8$

$A=408$

Therefore, the area of the trapezium is 408 square cm.

4 0

3 years ago

What is 3 × 8000283743729.

Keith_Richards [23]

Dear user,

3 × 8000283743729 = 2.4000851

7 0

3 years ago

Read 2 more answers

What is the interquartile rang of the following data set? 9,30,2,48,42,18,81,5,55,73,11

ycow [4]

30 is the real answer

6 0

2 years ago

Find the value of B - A if the graph of Ax + By = 3 passes through the point (-7, 2), and is parallel to the graph x + 3y = -5.

Elena-2011 [213]

Answer:

$B - A = -6$

Step-by-step explanation:

Given

Point: (-7,2)

x + 3y = -5

Required

Find B- - A in Ax + By = 3

To start with; we need to calculate the slope of x + 3y = -5

$x + 3y = -5$

Subtract x from both sides

$x - x + 3y = -5 - x$

$3y = -5 - x$

Divide both sides by 3

$\frac{3y}{3} = -\frac{5}{3} - \frac{x}{3}$

$y = -\frac{5}{3} - \frac{x}{3}$

The slope of the line is the coefficient of x

Slope = $- \frac{1}{3}$

The question says line Ax + By = 3 is parallel to line x + 3y = -5; This means that they have the same slope of $- \frac{1}{3}$

Having calculated the slope, next is to calculate the equation of the line using the following formula;

$m = \frac{y - y_1}{x - x_1}$

Where m is the slope; m = $- \frac{1}{3}$ ; $(x_1, y_1) = (-7,2)$

Substitute these values in the formula above; the formula becomes

$-\frac{1}{3} = \frac{y - 2}{x - -7}$

$-\frac{1}{3} = \frac{y - 2}{x +7}$

Cross Multiply

$-1(x+7) = 3(y-2)$

Open brackets

$-x - 7 = 3y - 6$

Add x to both sides

$x - x - 7 = 3y - 6 + x$

$-7 = 3y - 6 +x$

Add 6 to both sides

$-7 + 6 = 3y -6 + 6 + x$

$-1 = 3y + x$

Multipby both sides by -3

$-3(-1) = -3(3y + x)$

$3 = -9y - 3x$

$-9y - 3x = 3$

$-3x - 9y = 3$

Comparing the above to Ax + By = 3

$Ax = -3x\\A = -3$

$By = -9y\\B = -9$

$B - A = -9 - (-3)$

$B - A = -9 + 3$

$B - A = -6$

3 0

3 years ago