Here are 2, they simplify down to 3:2 so they are equivalent
6:4
9:6<span />
Secθ = cos^(-1)θ is the same as secθ = 1/cosθ
<span>Secant is a trigonometric function, reciprocal to the cosine
</span>
7b + 3
-4b + 5
+ -3b + 2
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10
Answer is choice B. 10
Answer:
Step-by-step explanation:
4/5 + 1/3 = 17/15 decimal form: 1.13 mixed number form: 1 2/5
1/2 + 2/5 = 9/10 decimal form: 0.9
3/4 + 7/10 = 29/20 decimal from: 1.45 mixed number form: 1 9/20
5/6 + 3/5 = 43/30 decimal form: 43/30 decimal form: 1.43 mixed number form: 1 13/30
1/5 + 1/4 = 9/20 decimal form: 0.45
1/4 + 5/9 = 29/36 decimal form: 0.805
2/3 + 7/8 = 37/24 decimal form: 1.5416 mixed number form: 1 13/24
Mark me as brainliest please
Start with #47. To find the critical values, you must differentiate this function. x times (4-x)^3 is a product, so use the product rule. The derivative comes out to f '(x) = x*3*(4-x)^2*(-1) + (4-x)^3*1 = (4-x)^2 [-3x + 4-x]
Factoring this, f '(x) = (4-x)^2 [-3x+4-x]
Set this derivative equal to zero (0) and solve for the "critical values," which are the roots of f '(x) = (4-x)^2 [-3x+4-x]. (4-x)^2=0 produces the "cv" x=4.
[-3x+ (4-x)] = 0 produces the "cv" x=1. Thus, the "cv" are {4,1}.
Evaluate the given function at x: {4,1}. For example, if x=1, f(1)=(1)(4-1)^3, or 2^3, or 8. Thus, one of the extreme values is (1,8).
