Step-by-step explanation:
I think Rewrite the equation as
z
=
20
x
−
3
y
.
z
=
20
x
−
3
y
Ok so it is a standard deck of 52 cards. Theres 4 suites: Hearts, Spades, Clubs and Diamonds.
In each suite there is 13 cards: Ace, King, Queen, Jack, 10, 9, 8, 7, 6, 5, 4, 3, and 2. The probability of you choosing 5 hearts is most likely to be 5/52.
The answer to this question would be 6
A = {1, 3, 5, 7, 9} B = {2, 4, 6, 8, 10} C = {1, 5, 6, 7, 9} A ∩ (B ∪ C) =
vovikov84 [41]
A = {1, 3, 5, 7, 9}
B = {2, 4, 6, 8, 10}
C = {1, 5, 6, 7, 9}
(B ∪ C) = {1, 2, 4, 5, 6, 7, 8, 9, 10}
so
A ∩ (B ∪ C) = {1, 5, 7 , 9}
