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CaHeK987 [17]
3 years ago
10

Can someone help me please and thank you very much

Mathematics
1 answer:
GaryK [48]3 years ago
7 0

Answer:

7-(-3)= 10

7-3=4

59-(-1)= 60

-17-(6)= -11

Step-by-step explanation:

Hope this helps! :3

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Compare the fractions. Use &lt;, &gt;, or =.<br> 6<br> 1<br> 7<br> 7
AURORKA [14]

Answer:

-6/7 < -1/7

because it is more than negative one by seven

8 0
3 years ago
The length of a rectangle is 3cm more than twice the width. The perimeter of the rectangle is 42 cm. Find the dimensions of the
bogdanovich [222]
The width is 6cm
And the length is two times + 3 of the width
6 X 2 + 3 = 15
Add all 4 sides for the perimeter 6+6+15+15=42
The the dimensions are a rectangle that is 6cm wide and 15cm tall
5 0
3 years ago
In AOPQ, m2O = (2x – 5)º, m P = (3x – 8)°, and mZQ = (10x – 17).<br> What is the value of x?
Misha Larkins [42]

9514 1404 393

Answer:

  x = 14

Step-by-step explanation:

The sum of angles in a triangle is 180°:

  ∠O +∠P +∠Q = 180°

  (2x -5)° +(3x -8)° +(10x -17)° = 180°

  15x -30 = 180 . . . . . divide by °, collect terms

  x -2 = 12 . . . . . . . . . divide by 15

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3 0
3 years ago
Is w^2-9w+81 a trinomial square
Yuri [45]
No because it would be
if you knew that
ax^2+bx+c was a trinomial square, then the factored form would be
( \sqrt{a}x+ \sqrt{c})^{2} or ( \sqrt{a}x- \sqrt{c})^{2}
so
if w^2-9w+81 is perfect square, factored form is either
( \sqrt{1}x+ \sqrt{81})^{2} or ( \sqrt{1}x- \sqrt{81})^{2}  aka ( x+9)^{2} or  ( x-9)^{2}
expand them
(x+9)^2=x^2+18x+81, wron middle term

(x-9)^2=x^2-18x+81 wrong

so it is not






8 0
3 years ago
Two lines, A and B, are represented by the following equations:
almond37 [142]

Answer:

D.

Step-by-step explanation:

The solution is where the lines intersect which is at the point (3,2).

So the answer is Option D.

The point (3,2) satisfies both equations.

4 0
3 years ago
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