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Kamila [148]
3 years ago
8

What is the mode for the data set?

Mathematics
2 answers:
navik [9.2K]3 years ago
3 0
Mode is the number that most occurs in the data. From the given data set, there is no repeated number. Thus, there is no mode for the data set.
Ann [662]3 years ago
3 0

Answer:

I just took the test the answer is: None

Step-by-step explanation:

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This trapezoid-based right pyramid has a volume of 48m³. What is the area of the base of the pyramid?
zhenek [66]

Answer:

18m^3

Step-by-step explanation:

Khan Academy

5 0
3 years ago
The weight of meteorite A is 5 times the weight of meteorite B. If the sum of their weights is 126 tons, find the weight of each
Sholpan [36]

Answer:

Step-by-step explanation:

if you divide 126 by 5, you get Meteorite B, 25.2, then minus that from 132, and you get Meteorite A, 106.8

To check, do 25.2 x 5 and you should get 132.

5 0
2 years ago
Can someone please help me with Evaluate |5| - |-5|.
Trava [24]

Answer:

|5| = 5

|-5| = 5

5-5

5

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
X/5 - 12 = -8 x=? what​
lutik1710 [3]
X = 20

If you multiply both sides by 5 to get rid of the fraction ( x - 60 = -40 ) the answer would become clear.
4 0
3 years ago
A metal hollow bar whose cross section and dimension are shown below weighs 8x10^3 kg/m^3 and measure 2m in length ..determine t
devlian [24]
1) We calculate the volume of a metal bar (without the hole).

volume=area of hexagon x length
area of hexagon=(3√3 Side²)/2=(3√3(60 cm)²) / 2=9353.07 cm²
9353.07 cm²=9353.07 cm²(1 m² / 10000 cm²)=0.935 m²

Volume=(0.935 m²)(2 m)=1.871 m³

2) we calculate the volume of the parallelepiped

Volume of a parallelepiped= area of the section  x length
area of the section=side²=(40 cm)²=1600 cm²
1600 cm²=(1600 cm²)(1 m² / 10000 cm²=0.16 m²
Volume of a parallelepiped=(0.16 m²)(2 m)=0.32 m³

3) we calculate the volume of a metal hollow bar:
volume of a metal hollow bar=volume of a metal bar -  volume of a parallelepiped

Volume of a metal hollow bar=1.871 m³ - 0.32 m³=1.551 m³

4) we calculate the mass of the metal bar

density=mass/ volume  ⇒ mass=density *volume

Data:
density=8.10³ kg/m³
volume=1.551 m³

mass=(8x10³ Kg/m³ )12. * (1.551 m³)=12.408x10³ Kg

answer: The mas of the metal bar is 12.408x10³ kg  or   12408 kg  


4 0
3 years ago
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