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3 years ago

3/7(b+2)-6/7(b-2)=CAN SOMEONE HELP SOLVE?

Mathematics

1 answer:

____ [38]3 years ago

4 0

3/7(b+2)-6/7(b-2)=

$\frac{3}{7(b+2)} -\frac{6}{7(b-2)}$

Here we find lcd first

lcd = 7(b+2)(b-2)

converting into lcd form we get,

$\frac{3(b-2)}{7(b+2)(b-2)} -\frac{6(b+2)}{7(b-2)(b+2)}$

= $\frac{(3b-6)}{7(b+2)(b-2)} -\frac{(6b+12)}{7(b-2)(b+2)}$

= $\frac{3b-6-6b-12}{7(b+2)(b-2)}$

= $\frac{-3b-18}{7(b+2)(b-2)}$

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3 years ago

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Binomial probability formula :-

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$P(X\leq4)=P(x=0)+P(x=1)+P(x=2)+P(x=3)+P(x=4)\\\\=^{15}C_{0}\ (0.30)^0(0.70)^{15}+^{15}C_{1}\ (0.30)^1(0.70)^{14}+^{15}C_{2}\ (0.30)^2(0.70)^{13}+^{15}C_{3}\ (0.30)^3(0.70)^{12}+^{15}C_{4}\ (0.30)^4(0.70)^{11}\\\\=(0.30)^0(0.70)^{15}+15(0.30)^1(0.70)^{14}+105(0.30)^2(0.70)^{13}+455(0.30)^3(0.70)^{12}+1365(0.30)^4(0.70)^{11}\\\\=0.515491059227\approx0.5$

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3 years ago

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bogdanovich [222]

The 3rd answer, is correct.

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4 years ago