x = the number of miles
y = the total cost
Company A:
0.60x + 60 = y [Company A charges $60 plus $0.60 per mile(x)]
Company B:
0.90x + 30 = y [Company B charges $30 plus $0.90 per mile(x)]
To find the number of miles where the costs for both companies are the same, you can set the equations equal to each other as the costs(y) are the same:
y = y Substitute the equations into "y" (substitute (0.60x + 60) and (0.90x + 30) into "y" since y = 0.60x + 60 and y = 0.90x + 30)
0.60x + 60 = 0.90x + 30 To find x, isolate/get the variable "x" by itself. Subtract 30 on both sides
0.60x + 60 - 30 = 0.90x + 30 - 30
0.60x + 30 = 0.90x Subtract 0.60x on both sides to get "x" on one side of the equation
0.60x - 0.60x + 30 = 0.90x - 0.60x
30 = 0.30x Divide 0.30 on both sides to get "x" by itself
100 = x 100 miles
(if you need to find out the cost where both companies cost the same, you can substitute/plug in the value of x into one of the equations.)
0.60x + 60 = y Plug in 100 into "x" since x = 100
0.60(100) + 60 = y
120 = y At 100 miles, both companies cost $120
100/20=5
11×5=55
11/20 = 0.55
Answer:
At most, Liam can only buy lunch for 6 people.
Step-by-step explanation:
It isn't going to be a decimal answer because there can't be half of a person
All you have to do is divide 50 by 8 and round down because you don't want to spend more than 50 dollars.
Writing it mathematically, it would be:
p 
6
A = L * W
A = 50
L = 2W
50 = W(2W)
50 = 2W^2
50/2 = W^2
25 = W^2
sqrt 25 = W
5 = W
L = 2W
L = 2(5)
L = 10 <==length is 10 yd
The range would be the difference between the lowest age and the highest age.
The highest age is 76, the lowest age is 30
The range is 76 - 30 = 46
