Answer:
0.643
Step-by-step explanation:
Let, s = play a sport
c = participate in a club
P(s) = 0.14
P(s n c) = 0.09
probability that a student participates in
a club given that they also play a sport = P(c | s)
P(c | s) = P(c n s) / P(s)
P(c | s) = 0.09 / 0.14
P(c | s) = 0.64285
= 0.643
Answer:
52 inches
Step-by-step explanation:
A.) P(defective | foo) = P(defective & foo)/P(foo)
4% = P(defective & foo)/30% . . . . . . . . . plug in the given data
0.04*0.30 = P(defective & foo) = 0.012 = 1.2%
The probability that a widget was produced at the foo factory and is defective is 1.2%.
b.) P(defective | foo) ≠ P(defective) (4% ≠ 5%), so the events P(defective) and P(foo) are NOT independent.
c.) P(foo | defective) = P(defective & foo)/P(defective)
P(foo | defective) = 1.2%/5% = 24%
The probability that a widget was produced at the foo factory given it is defective is 24%.
Answer:
The probability of scoring 1, 3, or 5 points with one randomly thrown dart is equal to divide the area of the largest circle by the area of the square game board
step 1:
Find the area of the square game board
"A=b^{2}"
we have
b=20cm
"substitute"
A=20^{2}
=400cm²
step 2:
Find the probability
P=314/400
=0.785
=0.785 x 100
=78.5%
