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max2010maxim [7]
1 year ago
5

100 grams/day of substance x is filtered, 50 grams/day is reabsorbed, 75 grams/day is secreted and 125 grams/day is excreted. su

bstance x is undergoing in the nephron and would have a clearance value that is .(choose one)
Mathematics
1 answer:
Ivan1 year ago
3 0

100 grams/day of substance x is filtered, 50 grams/day is reabsorbed, 75 grams/day is secreted and 125 grams/day is excreted. substance x is undergoing in the nephron net secretion and would have a clearance value that is greater than GFR

The formula for calculating clearance is Cx is given in terms of volume per time, where Ax is the quantity of x removed from the plasma, Px is the average plasma concentration, and Cx = Ax /Px.

Ax= 125 grams/day

and Px= 50 grams/day

Cx= 125/ 50

Cx= 2.5 grams/day

Therefore, the creatinine clearance overestimates GFR more severely in patients with a very low GFR than in those with higher GFR values. For a patient with a very low GFR, the secreted component is a relatively larger fraction of the total amount excreted.

Creatinine clearance remains the most popular method for routinely assessing patient GFR and the integrity of renal filtration, despite its low cost and convenience.

For more information on clearance kindly visit to

brainly.com/question/29461581

#SPJ4

Complete question :

Patient was experiencing respiratory acidosis (the increased hydrogen ion concentration was predominantly activating his peripheral chemoreceptors). 100 grams/day of substance X is filtered, 50 grams/day is reabsorbed, 75 grams/day is secreted and 125 grams/day is excreted. Substance X is undergoing ___________ in the nephron and would have a clearance value that is _________.(choose one)

A)net reabsorption, less than GFR

B)net secretion, greater than GFR

C)neither net reabsorption nor net secretion, equal to GFR

D)net reabsorption, greater than GFR

E) net secretion, less than GFR

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6 0
3 years ago
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7 0
4 years ago
The third term of an arithmetic sequence is equal to 9 and the sum of the first 8 term is 42. Find the first term and the common
zloy xaker [14]

Answer:

The first term is 14

The common difference is -2.5

Step-by-step explanation:

we know that

The rule to calculate the an term in an arithmetic sequence is

a_n=a_1+d(n-1)

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d is the common difference

a_1 is the first term

we have that

The third term of an arithmetic sequence is equal to 9

so

a_3=9

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substitute

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10.5=2a_1+7d ----> equation B

Solve the system by graphing

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using a graphing tool

the solution is (14,-2.5)

see the attached figure

therefore

a_1=14\\d=-2.5

The first term is 14

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