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Dima020 [189]
3 years ago
12

Jayson used 0.5 cup of kernels to make

Mathematics
2 answers:
Dennis_Churaev [7]3 years ago
6 0

The right answer is Option C.

Step-by-step explanation:

Cups of kernel used = 0.5

Cups of popcorn made = 16

Ratio of kernel used to popcorn made = 0.5:16

New cups of kernel used = 0.75

Let,

x be the new number of cups of popcorn.

Ratio of kernels to popcorn made = 0.75:x

Using proportion,

Ratio of kernel used to popcorn made :: Ratio of kernel to popcorn

0.5:16::0.75:x

Product of mean = Product of extreme

16*0.75=0.5*x\\12=0.5x\\0.5x=12\\

Dividing both sides by 0.5

\frac{0.5x}{0.5}=\frac{12}{0.5}\\x=24

24 cups of popcorn can be made from 0.75 cups of kernels.

The right answer is Option C.

Keywords: Ratio, proportion

Learn more about ratios at:

  • brainly.com/question/10940255
  • brainly.com/question/10941043

#LearnwithBrainly

Grace [21]3 years ago
3 0

28 cups

Step-by-step explanation:

cause i said so

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Answer:

Circumcenter =(-1,0)

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Step-by-step explanation:  

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Formula used :  

→Mid point of two points- (\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})

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Circumcenter- The point where the perpendicular bisectors of a triangle meets.

Orthocenter-The intersecting point for all the altitudes of the triangle.

To find out the circumcenter we have to solve any two bisector equations.

We solve for line AB and AC

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Mid point of AC = (\frac{2+2}{2},\frac{3-3}{2})=(2,0)

Slope of AC = \frac{-3-3}{2-2}=\frac{-6}{0}  

Slope of the bisector is the negative reciprocal of the given slope.  

So, the slope of the perpendicular bisector = 0  

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(y – 0) = 0(x – 2)  

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To find the orthocenter we solve the intersections of altitudes.

We solve for line AB and BC

So, mid point of AB =(\frac{2-4}{2},\frac{3-3}{2})=(-1,0)

Slope of AB =\frac{-3-3}{-4-2}=1

Slope of the bisector is the negative reciprocal of the given slope.  

So, the slope of CF = -1  

Equation of AB with slope -1 and the coordinates (-1,0) gives equation CF  

(y – 0) = -1(x – (-1))  

y+x=-1………………(3)  

Similarly, mid point of BC =(\frac{-4+2}{2},\frac{-3-3}{2})=(-1,-3)

Slope of AB =\frac{-3+3}{-4-2}=0

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(y-(-3)) = 0(x – (-1))  

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Put y=-3 in equation (3)

y+x=-1

-3+x=-1

x=2

Therefore, orthocenter(O)= (2,-3)


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