Four students are competing in a race. In how many different combinations could the four students place in the race?

Help! It says that I need to determine If both equations represent lines which are parallel, perpendicular, or none...

12345 [234]

4x + 2y = 8 (1)
 8x + 4y = -4y (2)

A) Two lines are parallel if they have the same gradient
- putting both equations into the gradient- intercept form ( y = mx + c where m is the gradient)
(1) 4x + 2y = 8
 2y = 8 - 4x
y = -2x + 4

 (2) 8x + 4y = -4y
 8x = -4y - 4y
y = $\frac{-8x}{-8}$
y = -x
Thus the gradient of the two equations are different and as such the two lines are not parallel

B) When two lines are perpendicular, the product of their gradient is -1
$m_{1} * m_{2} = p$
p = (-2) * (-1)
p = 2
 ∴ the two lines are not perpendicular either.

Thus these lines are SKEWED LINES

4 0

3 years ago

If a median, an altitude, and an angle bisector are the same segment in a triangle, the triangle is scalene

statuscvo [17]

Never is the right answer .

3 0

3 years ago

It is important that face masks used by firefighters be able to withstand high temperatures because firefighters commonly work i

USPshnik [31]

Answer:

The 93% confidence interval for the true proportion of masks of this type whose lenses would pop out at 325 degrees is (0.3154, 0.5574). This means that we are 93% sure that the true proportion of masks of this type whose lenses would pop out at 325 degrees is (0.3154, 0.5574).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

For this problem, we have that:

$n = 55, \pi = \frac{24}{55} = 0.4364$

93% confidence level

So $\alpha = 0.07$ , z is the value of Z that has a pvalue of $1 - \frac{0.07}{2} = 0.965$ , so $Z = 1.81$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.4364 - 1.81\sqrt{\frac{0.4364*0.5636}{55}} = 0.3154$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.4364 + 1.81\sqrt{\frac{0.4364*0.5636}{55}} = 0.5574$

The 93% confidence interval for the true proportion of masks of this type whose lenses would pop out at 325 degrees is (0.3154, 0.5574). This means that we are 93% sure that the true proportion of masks of this type whose lenses would pop out at 325 degrees is (0.3154, 0.5574).

8 0

3 years ago

Jessica drank 1/8 gallon of orange juice

irakobra [83]

And what else you can not solve that problem

6 0

3 years ago

If AABC is reflected across the yaxis, what are the coordinates of A?

Airida [17]

Answer:

A lies on (1,3) a reflection across the y-axis is (x,y) to (-x,y). The x turns the opposite and y stays the same so...

(-1,3)

5 0

3 years ago