Answer:
Option 1
Step-by-step explanation:
The formula of constant porpotionality is

or

where k is the constant of porpotionality.
This equation is direct variation so we will use

The equation is in the form

1.5 is in k place so the constant of porpotionality is 1.5
16 • (x^2 + 2y^4) • (x^2 - 2y^4)
Answer:
<em>Two possible answers below</em>
Step-by-step explanation:
<u>Probability and Sets</u>
We are given two sets: Students that play basketball and students that play baseball.
It's given there are 29 students in certain Algebra 2 class, 10 of which don't play any of the mentioned sports.
This leaves only 29-10=19 players of either baseball, basketball, or both sports. If one student is randomly selected, then the propability that they play basketball or baseball is:

P = 0.66
Note: if we are to calculate the probability to choose one student who plays only one of the sports, then we proceed as follows:
We also know 7 students play basketball and 14 play baseball. Since 14+7 =21, the difference of 21-19=2 students corresponds to those who play both sports.
Thus, there 19-2=17 students who play only one of the sports. The probability is:

P = 0.59
Answer:
66 galletas
Step-by-step explanation:
Si 3/11 de una caja contiene 18 galletas entonces matematicamente significa que:

Donde g son las galletas, ahora vamos a aislar la variable g:

Entonces una caja contiene 66 galletas
Using the information given above, the sampling distribution of the sample proportion of 100-ohm gold-band is 2.
- <em>Sampling distribution of proportion, P = 2% = 0.02 </em>
- <em>Sample size, n = 100</em>
<u>The sampling distribution of the sample proportion can be calculated thus</u>:
- <em>Distribution of sample proportion = np</em>
Distribution of sample proportion = (100 × 0.02) = 2
Therefore, there is a probability that only 2 of the samples will have resistances exceeding 105 ohms.
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