Answer: y=1
Explanation: all you have to do is plug in “-1” where x is. So you get: y=2(-1) +3.
Simplify and you have -2+3 which is 1
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~ Luna
The <em>quadratic</em> function g(x) = (x - 5)² + 1 passes through the points (2, 10) and (8, 10) and has a vertex at (5, 1).
<h3>How to analyze quadratic equations</h3>
In this question we have a graph of a <em>quadratic</em> equation translated to another place of a <em>Cartesian</em> plane, whose form coincides with the <em>vertex</em> form of the equation of the parabola, whose form is:
g(x) = C · (x - h)² - k (1)
Where:
- (h, k) - Vertex coordinates
- C - Vertex constant
By direct comparison we notice that (h, k) = (5, 1) and C = 1. Now we proceed to check if the points (x, y) = (2, 10) and (x, y) = (8, 10) belong to the parabola.
x = 2
g(2) = (2 - 5)² + 1
g(2) = 10
x = 8
g(8) = (8 - 5)² + 1
g(8) = 10
The <em>quadratic</em> function g(x) = (x - 5)² + 1 passes through the points (2, 10) and (8, 10) and has a vertex at (5, 1).
To learn more on parabolae: brainly.com/question/21685473
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Answer:
Which of the following is a common sign that a chemical change has occurred?
Step-by-step explanation:
rodrickkkkkkkkkkkkkk
Answer:
-5
Step-by-step explanation:
2 - 1 = 1
5 - 10 = -5
-5 divided by 1 = -5
Answer:
any coordinate outside the parabola is a reasonable answer.
Step-by-step explanation:
test the solution (0, 0) and if if that number is greater than 0 then the rest of the points outside on the inside are.
x = 0
y = 0
(0)^2 - 2(0) - 3 = -3
-3 is less than 0 so (0, 0) is not a possibility so any coordinate outside the parabola is a reasonable answer.
