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sweet [91]
3 years ago
15

Two consecutive intergers have a sum of 79, find the intergers

Mathematics
1 answer:
aev [14]3 years ago
6 0

Answer:

<em>The integers are 39 and 40.</em>

Step-by-step explanation:

Let the smaller integer be x.

The next greater integer is x + 1.

Their sum is x + x + 1.

Their sum is 79, so

x + x + 1 = 79

Solve for x.

2x + 1 = 79

2x = 78

x = 39

x + 1 = 40

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Write expression as the logarithm of a single number<br> log6 + log8 - log2
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<h2>log (6 ) + log ( 8 ) − log ( 2 ) </h2><h2 /><h2>  Answer:</h2>

Exact Form:    ㏒ ( 24 )

Decimal Form:    1.38021124


<h2>Explanation:</h2><h3>                            Use the product property of logarithms,  </h3>

                                ㏒b ( x)  +  ㏒b ( y )  =  ㏒b ( x y ).

                                 ㏒ ( 6 ⋅ 8 ) −  ㏒ ( 2 ) .


<h3>                         ⇒Use the quotient property of logarithms,</h3>

                                 ㏒ b ( x ) − ㏒ b ( y ) = ㏒ b ( x y ) .

                                 ㏒ ( 6 ⋅ 8/ 2 )

<h3>                          ⇒Reduce the expression by cancelling the common factors. </h3>

                                Factor  2  out of  6 ⋅8 .

                                log ( 2 ( 3 ⋅ 8 )  / 2 )

<h3>                             Divide  3 ⋅ 8   by  1 .</h3>

                                ㏒ ( 3 ⋅ 8 )

                                Multiply  3  by  8 .

                                 ㏒ ( 24 )

<h3>The result can be shown in both exact and decimal forms. </h3><h3>                            Exact Form:  ㏒ ( 24 ) </h3><h3>                            Decimal Form:  1.38021124</h3>
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