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2 years ago

Two consecutive intergers have a sum of 79, find the intergers

Mathematics

1 answer:

aev [14]2 years ago

6 0

Answer:

The integers are 39 and 40.

Step-by-step explanation:

Let the smaller integer be x.

The next greater integer is x + 1.

Their sum is x + x + 1.

Their sum is 79, so

x + x + 1 = 79

Solve for x.

2x + 1 = 79

2x = 78

x = 39

x + 1 = 40

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There are 14 girls and 2 boys taking karate lessons. Write the ratio that compares the number of girls taking karate lessons to

Delvig [45]

Answer:

The correct answer is 7 : 8.

Step-by-step explanation:

There are 14 girls and 2 boys taking karate lessons.

Total number of students taking the karate class is 16.

The ratio that compares the number of girls taking karate lessons to the total number of students taking karate lessons is given by 14 : 16 = 7 : 8.

This can be interpreted as for every 8 students in the karate lesson, 7 of them are girls.

8 0

3 years ago

Translate the sentence into an equation.

nekit [7.7K]

Answer:

6c - 7 = 5

Step-by-step explanation:

following the steps in the sentence.

because it is 7 less you have a subtraction problem ( -7)

because it is 6 and a number you have a multiplication problem (6c)

it equals 5 (=5)

8 0

2 years ago

Solve x^2 - x - 5/2 = 0 using the quadratic formula.

Soloha48 [4]

Using the quadratic formula, we have:

$\frac{1+- \sqrt{11} }{2}$ , so our solutions are $\frac{1+ \sqrt{11} }{2}$ and $\frac{1- \sqrt{11} }{2}$ .

5 0

3 years ago

During a sale, a grocery store gives every 13th customer a free loaf of bread. If 910 customers visit the store, how many loaves

goldfiish [28.3K]

Answer:70

Step-by-step explanation:910/13=70 so he gives away 70 loafs of bread.

5 0

2 years ago

A veterinarian wants to know if pit bulls or golden retrievers have a higher incidence of tooth decay at the age of three. The v

BigorU [14]

Answer: B) [-0.0332,0.1332]

Step-by-step explanation: Confidence Interval is an interval where we can be a percentage sure the true mean is.

The confidence interval for a difference in population proportion is calculated following these steps:

First, let's find population proportion for each population:

$p_{1}=\frac{30}{120}=0.25$

$p_{2}=\frac{32}{160}=0.2$

Second, calculate standard deviation for each proportion:

$\sigma_{1}=\sqrt{\frac{0.25(0.75)}{120} } = 0.0395$

$\sigma_{2}=\sqrt{\frac{0.2(0.8)}{160} } = 0.0316$

Now, we calculate standard error for difference:

$SE=\sqrt{\sigma_{1}^{2}+\sigma_{2}^{2}}$

$SE=\sqrt{0.0395^{2}+0.0316^{2}}$

SE = 0.0505

The z-score for a 90% CI is 1.645.

Then, confidence interval is

$p_{1}-p_{2}$ ± z-score.SE

$0.25-0.2$ ± $1.645(0.0505)$

0.05 ± 0.0831

The limits of this interval are:

inferior: 0.05 - 0.0831 = $-0.0332$

superior: 0.05 + 0.0831 = 0.1332

The 90% confidence interval for the difference in the population proportion of pit pulls and golden retrievers is $[-0.0332,0.1332]$ .

8 0

2 years ago