All categories

3 years ago

Two consecutive intergers have a sum of 79, find the intergers

Mathematics

1 answer:

aev [14]3 years ago

6 0

Answer:

The integers are 39 and 40.

Step-by-step explanation:

Let the smaller integer be x.

The next greater integer is x + 1.

Their sum is x + x + 1.

Their sum is 79, so

x + x + 1 = 79

Solve for x.

2x + 1 = 79

2x = 78

x = 39

x + 1 = 40

You might be interested in

3. You are saving money to buy a new bike that costs $360. You

katen-ka-za [31]

Answer:

Step-by-step explanation:360-85=275, 275 divided by 12.

3 0

2 years ago

1/2x + 1/3y = 5 1/4x + y = 10

Pavel [41]

The answer for your question is (x,y)=(4,9)

8 0

3 years ago

Read 2 more answers

In order to attract more advertisers to the arena during the sports events, the arena plans to offer advertising space as corpor

beks73 [17]

720 divided by 8 and then look up the answer to that as a fraction on Google

3 0

3 years ago

Read 2 more answers

Iteration - Maths Question attached

Ivanshal [37]

Answer:

7.8

Step-by-step explanation:

First I will try 50. I got 127,550, so that was way too big.

Let me try a smaller number. How about 5. I got 155, so that was a bit too small.

Now I'll try 20. I got 8420. Looks like the number is between 5 and 20.

How about 7. I got 399.

Let me try 8. I got 584! That's really close. It's just a little too big.

I tried 7.5, and got 485.624. So close! Just a little higher.

Putting in 7.8 yields 543.192! That's our answer.

8 0

3 years ago

Suppose 52% of the population has a college degree. If a random sample of size 563563 is selected, what is the probability that

amm1812

Answer:

The value is $P(| \^ p - p| < 0.05 ) = 0.9822$

Step-by-step explanation:

From the question we are told that

The population proportion is $p = 0.52$

The sample size is n = 563

Generally the population mean of the sampling distribution is mathematically represented as

$\mu_{x} = p = 0.52$

Generally the standard deviation of the sampling distribution is mathematically evaluated as

$\sigma = \sqrt{\frac{ p(1- p)}{n} }$

=> $\sigma = \sqrt{\frac{ 0.52 (1- 0.52 )}{563} }$

=> $\sigma = 0.02106$

Generally the probability that the proportion of persons with a college degree will differ from the population proportion by less than 5% is mathematically represented as

$P(| \^ p - p| < 0.05 ) = P( - (0.05 - 0.52 ) < \^ p < (0.05 + 0.52 ))$

Here $\^ p$ is the sample proportion of persons with a college degree.

$P( - (0.05 - 0.52 ) < \^ p < (0.05 + 0.52 )) = P(\frac{[[0.05 -0.52]]- 0.52}{0.02106} < \frac{[\^p - p] - p}{\sigma } < \frac{[[0.05 -0.52]] + 0.52}{0.02106} )$