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3 years ago

8

Please help me with my homework please answer this correctly

1 answer:

Eduardwww [97]3 years ago

7 0

12,601 should be right

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Somone please help me asap i need to turn this in its due tomorrow

Novosadov [1.4K]

Hope this helps !
Answer circled on green

6 0

3 years ago

SOMEONE PLEASE HELP ME WITH THIS!!!!

navik [9.2K]

<em>Answer:</em>

<em>It is C</em>

<em>Step-by-step explanation: The explanation says that he subtracted 10 by 20 and divided by 5 so the real answer is 18 but the answer in your page is C </em>

<em>Your Welcome :)</em>

<em />

3 0

3 years ago

A square is inscribed in a circle. If the area of the square is 9 in2, what is the ratio of the circumference of the circle to t

IgorC [24]

The ratio of the circumference of the circle to the perimeter of the square is $\pi \sqrt{2}:4$

<em><u>Explanation</u></em>

Area of the square = 9 inch²

If the side length of the square is $a$ , then

$a^2 = 9 \\ \\ a= \sqrt{9} =3$

So the side length of the square is 3 inch.

Now as the square is inscribed in a circle, so the diagonal of the square will be diameter of the circle.

Length of the diagonal of square = $a\sqrt{2} = 3\sqrt{2}$ inch

So, the diameter of the circle $= 3\sqrt{2}$ inch

If the radius of the circle is $r$ , then

$2r = 3\sqrt{2} \\ \\ r= \frac{3\sqrt{2}}{2}$

Circumference of the circle, $2\pi r= 2\pi *\frac{3\sqrt{2}}{2}= 3\pi \sqrt{2}$ inch

and Perimeter of the square, $4a = (4*3)inch= 12$ inch

So, the ratio will be: $3\pi \sqrt{2} : 12 = \pi \sqrt{2} : 4$

8 0

4 years ago

Read 2 more answers

Match the vocabulary word with its definition.

trapecia [35]

<span>1. fractions with the same numerical value; fractions that are equal to each other - "Equivalent Fractions"

2. </span><span>a fraction in lowest terms - "Simplest form"

Hope this helps!</span>

5 0

3 years ago

Read 2 more answers

Which are the solutions of x2 = –11x + 4?

Zarrin [17]

For this case we have the following polynomial:

$x ^ 2 = -11x + 4$

Rewriting the polynomial we have:

$x ^ 2 + 11x - 4 = 0$

From here, we can solve the polynomial using the quadratic equation

We have then:

$x=\frac{-b+/-\sqrt{b^2-4ac}}{2a}$

$x=\frac{-11+/-\sqrt{11^2-4(1)(-4)}}{2(1)}$

$x=\frac{-11+/-\sqrt{11^2+16}}{2}$

$x=\frac{-11+/-\sqrt{121+16}}{2}$

$x=\frac{-11+/-\sqrt{137}}{2}$

Therefore, the solutions are:

$x=\frac{-11+\sqrt{137}}{2}$

$x=\frac{-11-\sqrt{137}}{2}$

5 0

4 years ago

Read 2 more answers