<span>Hello : let
A(5,-4) B(-1,8)
the slope is : (YB - YA)/(XB -XA)
(8+4)/(-1-5) =-2
an equation is : y=ax+b a is a slope</span>
y = -2x +b
the line through point A(5,-4) :
-4= -2(5)+b<span>
<span>b = 6
the equation is : y =-2x+6</span></span>
It is a reduction of the original because it became a smaller figure. The scale factor would be less than 1 because it is shrunken I would say the scale factor is 1/2
Answer=D
Most fruits and vegetables have a high water content. For example, ice berg lettuce is 96% water. And of course water is totally fluid...
Let,
f(x) = -2x+34
g(x) = (-x/3) - 10
h(x) = -|3x|
k(x) = (x-2)^2
This is a trial and error type of problem (aka "guess and check"). There are 24 combinations to try out for each problem, so it might take a while. It turns out that
g(h(k(f(15)))) = -6
f(k(g(h(8)))) = 2
So the order for part A should be: f, k, h, g
The order for part B should be: h, g, k f
note how I'm working from the right and moving left (working inside and moving out).
Here's proof of both claims
-----------------------------------------
Proof of Claim 1:
f(x) = -2x+34
f(15) = -2(15)+34
f(15) = 4
-----------------
k(x) = (x-2)^2
k(f(15)) = (f(15)-2)^2
k(f(15)) = (4-2)^2
k(f(15)) = 4
-----------------
h(x) = -|3x|
h(k(f(15))) = -|3*k(f(15))|
h(k(f(15))) = -|3*4|
h(k(f(15))) = -12
-----------------
g(x) = (-x/3) - 10
g(h(k(f(15))) ) = (-h(k(f(15))) /3) - 10
g(h(k(f(15))) ) = (-(-12) /3) - 10
g(h(k(f(15))) ) = -6
-----------------------------------------
Proof of Claim 2:
h(x) = -|3x|
h(8) = -|3*8|
h(8) = -24
---------------
g(x) = (-x/3) - 10
g(h(8)) = (-h(8)/3) - 10
g(h(8)) = (-(-24)/3) - 10
g(h(8)) = -2
---------------
k(x) = (x-2)^2
k(g(h(8))) = (g(h(8))-2)^2
k(g(h(8))) = (-2-2)^2
k(g(h(8))) = 16
---------------
f(x) = -2x+34
f(k(g(h(8))) ) = -2*(k(g(h(8))) )+34
f(k(g(h(8))) ) = -2*(16)+34
f(k(g(h(8))) ) = 2
Answer:
Just so you hear, Whirlybot, these circle problems are always "tricks" and they are tough. You have to remember a bunch of implied things
Step-by-step explanation:
One thing to recall is that the angle from the tangent point to O at the center is also a 90° angle. so you now know, that the line from the point where the circle touches the tangent line to the center is a right angle and you have part of that 90° already. the 50 is one part and there for the next part is 40 ° Since we now know that the line from the tangent to the center is forming an internal angle with that line going to X of 40 ° we know that X is also 40 ° b/c the triangle formed by the line to the center is going to be the same length as the line from the center to the X. That's an Isosceles triangle. they have the same angles at the two same length legs.
I know, I went thur a whole pile of logic, but that's what makes this kind of problem tough. you just have to keep thinking about things you know.
X = 40 °
