<span>( 5, 2) and ( 6, 4)
slope m = (4-2)/(6-5) = 2
y = mx + b
b = y - mx
b = 2 - 2(5)
b = 2 - 10
b = -8
so now you have slope m = 2 and y intercept b = -8
equation
y = 2x - 8
answer
</span><span>a. y = 2x - 8</span>
The solutions fo the inequality are all the points (x, y) that meet these 3 conditions.
- x ≠ 0
- y ≠ 0
- Sign(x) =sign(y)
<h3>
Which points are solutions of the inequality?</h3>
We want to find points of the form (x, y) that are solutions of the inequality:
x*y > 0
Clearly x and y must be different than zero.
So, for example if x = -1, y can be any negative number, for example y= -3
x*y > 0
(-1)*(-3) > 0
3 > 0
This is true.
Now if x = 1, y must be positive. LEt's take y = 103, then:
x*y > 0
1*103 > 0
103 > 0
Then we have 3 conditions:
- x ≠ 0
- y ≠ 0
- Sign(x) =sign(y)
The solutions fo the inequality are all the points (x, y) that meet these 3 conditions.
If you want to learn more about inequalities:
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Answer:
Step-by-step explanation:
sum of angles of parallelogram=360 degrees
adjacent angles add up to 180 degrees (supplementary angles)
Angle A=104 (DAB=104)
Angle D=180-104=76 degrees (angle ADB)
Angle B=60 degrees
Angle C=180-60=120 (DCB)
Answer:
have an F- on math call for help!
Step-by-step explanation:
You are given a vector in the XY plane that has a magnitude of 87. 0 units and a y component of -66. 0 units. The direction of the vector V is;
<h3>How to know the direction of a vector?</h3>
We know that the formula for 2 vectors like this in the x and y directions is; A = xi^ + yj^
Where A is the magnitude of the resultant
x is the value of the x-component
y is the value of the y-component
We are given;
Magnitude of vector = 84 units
Y-component of the vector = -67 units
Thus,
From A above, let us take the positive value of the x-component and as such our original vector will be;
A = 56.68i^ - 66j^
The direction of the vector V is;
Since it points entirely to the negative x-axis, then the angle is;
180 - (-27.15) = 207.15°
Learn more about vectors;
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