Answer:
Average rate of change=\displaystyle \frac{\text{Change in output}}{\text{Change in input}}
Change in input
Change in output
=\displaystyle \frac{\Delta y}{\Delta x}
Δx
Δy
=\displaystyle \frac{{y}_{2}-{y}_{1}}{{x}_{2}-{x}_{1}}
x
2
−x
1
y
2
−y
1
=\displaystyle \frac{f\left({x}_{2}\right)-f\left({x}_{1}\right)}{{x}_{2}-{x}_{1}}
x
2
−x
1
f(x
2
)−f(x
1
)
8/1:3/5 (reciprocal)
8/1x5/3
=40/3
Since the trout is 4.8m below Jamal and it takes 1.5m just to get to the surface of the water, we will subtract the two numbers.
1.5 - 4.8 = - 3.3 The trout is 3.3 meters below the surface.
Answer:
Step-by-step explanation:
First let's find the value of 'p-q':
To find |p-q| (module of 'p-q'), we can use the formula:
Where 'a' is the coefficient of 'i' and 'b' is the coefficient of 'j'
So we have:
Now, we need to find the module of p and the module of q:
Then, evaluating |p-q|-{|p|-|q|}, we have:
Answer:
AB = 26.5º
Step-by-step explanation:
cosA = adj/hyp
cosA = AC/AB
cos41 = 20/AB
Multiply both sides by AB
AB * cos41 = 20
Divide both sides by cos41
AB = 20/cos41
AB = 26.5º
