By simplifying both sides of the equation then isolating the variable
Answer:
y=1/3x-2
Step-by-step explanation:
m=(y2-y1)/(x2-x1)
m=(0-(-2))/(6-0)
m=(0+2)/6
m=2/6
simplify
m=1/3
y-y1=m(x-x1)
y-(-2)=1/3(x-0)
y+2=1/3(x)
y+2=1/3x
y=1/3x-2
X= sandwiches
y= bottles of water
QUANTITY EQUATION
x+y= 200
COST EQUATION
$3x + $0.75y= $318.75
STEP 1
solve for one variable in quantity equation and substitute in cost equation
x+y= 200
subtract y from both sides
x= 200-y
STEP 2
substitute 200-y in for x
$3x + $0.75y= $318.75
3(200-y) + 0.75y= 318.75
600 - 3y + 0.75y= 318.75
combine like terms
600 - 2.25y= 318.75
-2.25y= -281.25
divide both sides by -2.25
y= 125 number of water bottles
STEP 3
substitute y=125 in either equation
x+y= 200
x + 125= 200
x= 75 sandwiches
ANSWER: There were 75 sandwiches and 125 bottles of water.
Hope this helps! :)
Solution:
iv) Given equation: 
Since we are given two variables, we need to split the original expression into two quadratic expressions as
Factoring x first:
= 
= 
Factoring y now:
= 
= ![-1[ y(y+1) + 1(y+1)]](https://tex.z-dn.net/?f=-1%5B%20y%28y%2B1%29%20%2B%201%28y%2B1%29%5D)
= ![-1 [(y+1)(y+1)]](https://tex.z-dn.net/?f=-1%20%5B%28y%2B1%29%28y%2B1%29%5D)
= 
Therefore, the original expression becomes
Answer:
1 4/5
Step-by-step explanation:
When you divide 9 into groups of 5, you have one whole group and 4/5 of a second group. Diagram is attached below.
