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3 years ago

What's the value of a?

Mathematics

1 answer:

Katena32 [7]3 years ago

4 0

$= {x}^{ \frac{4}{3} } \times {x}^{ \frac{1}{3} }$
$= {x}^{ \frac{5}{3} }$
so a = 5/3

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Need help asap please

Gwar [14]

Answer:

The answer is C

Step-by-step explanation:

3 0

3 years ago

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Write an equation for the line shown pictured in the graph.

guajiro [1.7K]

Answer:

4y = x + 13

Step-by-step explanation:

The general equation of the line y = mx + c

where m is the slope and c is constant represent y-intercept

The line shown in the graph pass through the points (3,4) , (-1,3)

The slope of the line = (y₂-y₁)/(x₂-x₁) = (3-4)/(-1-3) = -1/-4 = 1/4

∴ y = (1/4) x + c

Substitute with the point (3,4) to find c

∴ 4 = (1/4) 3 + c

∴ c = 4 - 3/4 = 13/4

∴ y = (1/4) x + 13/4 ⇒ multiply both sides by 4

∴ 4y = x + 13

So, The equation of the line in the graph: 4y = x + 13

The equation can be written as y = (1/4) x + 13/4 OR 4y - x = 13

8 0

4 years ago

In a certain region, the average movie theater ticket price in 2009 was $9.50. In 2008, it was $9.37. Find the increase in a

Oliga [24]

Answer:

$0.13

Step-by-step explanation:

The increase is the difference between the 2009 price and the 2008 price.

$9.50 - $9.37 = $0.13

4 0

3 years ago

HELP!!! Evaluate the function for x = 2 f(x)=7x-5 ISTG I WILL MARK BRAINLIEST!!!!

Tpy6a [65]

Answer:

Step-by-step explanation:

All you have to do is plug x = 2 into the equation so:

$7 * 2 - 5\\14 - 5\\9$

3 0

3 years ago

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Erica plotted the three towns closest to her house on a graph with town AA at (9, 12), town BB at (9, 7) and town CC at (1, 1).

Sliva [168]

To compute the distance between the points, we can apply the distance formula as shown below.

$d = \sqrt{(x_{1} - x_{2})^{2} + (y_{1} - y_{2})^{2} }$

In which x₁ and x₂ are the x-coordinates and y₁ and y₂ are the y-coordinates of the two points. Thus, applying this with the segments AABB, AACC, and BBCC, we have

$\overline{AABB} = \sqrt{(9-9)^{2} + (12-7)^{2}} = 5$
$\overline{AACC} = \sqrt{(9-1)^{2} + (12-1)^{2}} = \sqrt{185}$
$\overline{BBCC} = \sqrt{(9-1)^{2} + (7-1)^{2}} = 10$

Now that we have the lengths of all the sides of ΔAABBCC, we can find the missing angles using the Law of Cosines.

Generally, we have

$c^{2} = a^{2} + b^{2} - 2abcosC$

or

$C = cos^{-1} (\frac{a^{2} + b^{2} - c^{2}}{2ab})$

Hence, we have

$\angle AA = cos^{-1} (\frac{(\sqrt{185})^{2} + 5^{2} - 10^{2}}{2(5)(\sqrt185)})$
$\angle BB= cos^{-1} (\frac{5^{2} + 10^{2} - (\sqrt{185})^{2}}{2(5)(10)})$
$\angle CC= cos^{-1} (\frac{10^{2} + (\sqrt{185})^{2} - 5^{2}}{2(5)(\sqrt{185})})$

Simplifying this, we have

$\angle AA = 36.03^{0}$
$\angle BB = 126.87^{0}$
$\angle CC = 17.10^{0}$

Thus, from this, we can arrange the angles from smallest to largest: ∠CC, ∠AA, and ∠BB.

Answer: ∠CC, ∠AA, and ∠BB

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3 years ago