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Setler [38]
3 years ago
15

Jo says she can find the percent equivalent of 3/4 by multiplying the percentage equivalent of 1/4 by 3. How can you use a perce

ntage bar model to support this claim??
Mathematics
1 answer:
schepotkina [342]3 years ago
4 0
You can by filling 1 out of 4 bars then multiply the shaded bars by 3<span />
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Use the quadratic formula to find both solutions to the quadratic equation given below 2x^2-3x+1=0
kicyunya [14]
-2   +   -1   =   -3
<span>(2x2 - 3x) + 1 = 0
</span><span>(x - 1) • (2x - 1) = 0
</span>x-1=0
x = 1<span> </span>
5 0
3 years ago
Read 2 more answers
1.) (7.RP.3) Tracy started a savings account that is set up so that the simple interest earned on the investment is moved into a
amid [387]
<h3>Answer:</h3>

$450

<h3>Step-by-step explanation:</h3>

Each year, the amount of interest earned is ...

... 4.5% × $5000 = $225

After 2 years, a total of ...

... $225 × 2 = $450

has been transferred.

_____

<em>Comment on percentages</em>

Of course, you know that 4.5% = 4.5/100 = 45/1000 = 0.045.

You can think of the % symbol as a fancy (shorthand) way to write /100. (Likewise, the ‰ symbol means /1000.)

3 0
3 years ago
A tree was 5 feet tall. One year later, the tree was 13 feet tall. Write an equation and use mental math to find how many feet f
swat32
Just minus 5 feet from the new height which is 13ft, and the equation will be 13-5, and therefore the tree grew 8 feet
7 0
3 years ago
Read 2 more answers
Suppose that from the past experience a professor knows that the test score of a student taking his final examination is a rando
DENIUS [597]

Answer:

n=13.167^2 =173.369 and if we round up to the nearest integer we got n =174

Step-by-step explanation:

Previous concepts

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Let X the random variable who represents the test score of a student taking his final examination. We know from the problem that the distribution for the random variable X is given by:

X\sim N(\mu =73,\sigma =10.5)

From the central limit theorem we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

Solution to the problem

We want to find the value of n that satisfy this condition:

P(71.5 < \bar X

And we can use the z score formula given by:

z=\frac{\bar X- \mu}{\frac{\sigma}{\sqrt{n}}}

And we have this:

P(\frac{71.5-73}{\frac{10.5}{\sqrt{n}}} < Z

And we can express this like this:

P(-0.14286 \sqrt{n} < Z< 0.14286 \sqrt{n} )=0.94

And by properties of the normal distribution we can express this like this:

P(-0.14286 \sqrt{n} < Z< 0.14286 \sqrt{n} )=1-2P(Z

If we solve for P(Z we got:

P(Z

Now we can find a quantile on the normal standard distribution that accumulates 0.03 of the area on the left tail and this value is: z=-1.881

And using this we have this equality:

-1.881 = -0.14286 \sqrt{n}

If we solve for \sqrt{n} we got:

\sqrt{n} = \frac{-1.881}{-0.14286}=13.167

And then n=13.167^2 =173.369 and if we round up to the nearest integer we got n =174

6 0
3 years ago
Gino brings home one book from each of his 5 school subjects and places them side by side on a
const2013 [10]

Answer:

about 50

Step-by-step explanation:

that's all I can think of

4 0
3 years ago
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