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2 years ago

15

Jo says she can find the percent equivalent of 3/4 by multiplying the percentage equivalent of 1/4 by 3. How can you use a perce

ntage bar model to support this claim??

1 answer:

schepotkina [342]2 years ago

4 0

You can by filling 1 out of 4 bars then multiply the shaded bars by 3<span />

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A quadrilateral is a parallelogram only if both pairs of opposite sides are equal.

monitta

Answer:

True

Step-by-step explanation:

A parallelogram is a quadrilateral with 4 sides and both pairs of opposite sides are equal.

6 0

3 years ago

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The perimeter of a triangle is 104 units. The combined length of two of the sides of the triangle is 64 units.

valkas [14]

Answer:

Step-by-step explanation:

168

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1 year ago

The triangle has size with the lengths of 3 cm 13 cm and 14 cm Is it a right triangle?

WITCHER [35]

Answer:

No, it is not a right triangle

Step-by-step explanation:

Let H = 14 cm

B = 3 cm

P = 13 cm

According to pythagoras theorem:

H^2 = P^2 + B^2

14^2 = 13^2 + 3^2

196 = 169 + 9

196 is not equal to 178

Hence, it is not a right triangle

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2 years ago

Help me solve this-> g(x) = 2x + 3<br><br><br><br> g(7) =

kakasveta [241]

Answer:

17

Step-by-step explanation:

it's sufficient to set x=7

g(7)=2×7+3=14+3=17

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2 years ago

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Integrate the following

enot [183]

I suppose you mean to have the entire numerator under the square root?

$\displaystyle\int_2^4\frac{\sqrt{x^2-4}}{x^2}\,\mathrm dx$

We can use a trigonometric substitution to start:

$x=2\sec t\implies\mathrm dx=2\sec t\tan t\,\mathrm dt$

Then for $x=2$ , $t=\sec^{-1}1=0$ ; for $x=4$ , $t=\sec^{-1}2=\frac\pi3$ . So the integral is equivalent to

$\displaystyle\int_0^{\pi/3}\frac{\sqrt{(2\sec t)^2-4}}{(2\sec t)^2}(2\sec t\tan t)\,\mathrm dt=\int_0^{\pi/3}\frac{\tan^2t}{\sec t}\,\mathrm dt$

We can write

$\dfrac{\tan^2t}{\sec t}=\dfrac{\frac{\sin^2t}{\cos^2t}}{\frac1{\cos t}}=\dfrac{\sin^2t}{\cos t}=\dfrac{1-\cos^2t}{\cos t}=\sec t-\cos t$

so the integral becomes

$\displaystyle\int_0^{\pi/3}(\sec t-\cos t)\,\mathrm dt=\boxed{\ln(2+\sqrt3)-\frac{\sqrt3}2}$

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2 years ago