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tankabanditka [31]

3 years ago

15

(13)^2(13)^-4(13)^5 = 13?

2 answers:

alexdok [17]3 years ago

7 0

Answer:

13³

Step-by-step explanation:

The applicable rule of exponents is ...

(a^b)(a^c) = a^(b+c)

For your expression ...

13^2·13^-4·13^5 = 13^(2-4+5) = 13^3

Sergio039 [100]3 years ago

5 0

Answer:

no 2197

Step-by-step explanation:

(13)^2(13)^-4(13)^5 = 13?

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3 years ago

(a) Descriptive form: The set of natural numbers greater than or equal to 6.

olasank [31]

The set of natural numbers greater than or equal to 6 will be 6, 7, 8, 9, 10, ....

<h3>How to illustrate the information?</h3>

It should be noted that the first information is about the set of natural numbers greater than or equal to 6. Therefore, they will be 6 and above.

It should be noted that the descriptive form simply states in words the elements that are in a set. It is the verbal description of the elements in the set. It is the determination of the elements that belong to a set and those that doesn't.

Also, the way that a set is described is known as the roster form. In this case, the contents of a set can be described by listing the elements that are in the set which are separated by a comma inside the bracket.

Also, the roster form: (5, 7, 9, 11) indicates odd natural numbers. The numbers that are given are odd.

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8 0

11 months ago

1. A Babylonian tablet found in 1936 shows that the Babylonians sometimes used a more accurate value of π than 3. They determine

madreJ [45]

Answer:

<h2>1/4</h2>

Step-by-step explanation:

Area of a circle is given as πr² and its circumference is expressed as 2πr.

If the babylonians determined the area of a circle by taking it as equal to the square of the circle’s circumference then;

Area of circle = (circumference of a circle)²

πr² = (2πr)²

πr² = 4π²r²

Dividing both sides of the equation by πr² we have;

$\frac{\pi r^{2} }{\pi r^{2} } =\frac{4\pi^{2} r^{2} }{\pi r^{2} }\\1 = 4\pi \\\pi =\frac{1}{4}$

The value of π this yields is 1/4

6 0

3 years ago

7,14/5, 8/25 find the 7th term

tiny-mole [99]

I believe that would be 7

4 0

3 years ago

Prove that DJKL~ DJMN using SAS Similarity Theorem. Plot the points J (1,1), K(2,3), L(4,1) and J (1,1), M(3,5), N(7,1). Draw DJ

dolphi86 [110]

Answer and Step-by-step explanation: The triangles are plotted and shown in the attachment.

SAS Similarity Theorem is by definition: if two sides in one triangle are proportional to two sides of another triangle and the angles formed by those sides in each triangle is congruent, the triangles are similar.

For the triangles on the grid, we know that ΔJKL and ΔJMN have a congruent angle in J as shown in the image. To prove they are similar, we find the slope of sides KL and MN:

<u>Slope of KL</u>:

slope = $\frac{y_{K} - y_{L} }{x_{K} - x_{L} }$

slope = $\frac{3-1}{2-4}$

slope = -1

<u>Slope of MN</u>:

slope = $\frac{y_{N} - y_{M} }{x_{N} - x_{M} }$

slope = $\frac{1-5}{7-3}$

slope = -1

Since the slopes of KL and MN are the <u>same</u> and the angle is <u>congruent</u>, we can conclude that ΔJKL~ΔJMN.

5 0

2 years ago