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Montano1993 [528]
3 years ago
14

Solve for g.

Mathematics
1 answer:
Y_Kistochka [10]3 years ago
7 0

Answer:

g =6/5                           g=-5/2

Step-by-step explanation:

(5g − 6)(2g + 5) = 0

Using the zero product property

(5g − 6)  =0          (2g + 5) = 0

5g-6+6 =0+6             2g+5-5=0-5

5g =6                          2g =-5

5g/5 = 6/5                  2g/2 =-5/2

g =6/5                           g=-5/2

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On a recent trip, Cindy drove her car 290 miles, rounded to the nearest 10 miles, and used 12 gallons of gasoline, rounded to th
Pani-rosa [81]

Answer:

D.  \frac{285}{12.5} and \frac{295}{11.5}.

Step-by-step explanation:

We have been given that one a recent trip, Cindy drove her car 290 miles, rounded to the nearest 10 miles, and used 12 gallons of gasoline, rounded to the nearest gallon.

The range of miles driven would be between 285 because number of miles in rounded to nearest 10 miles.

The range of gallons of gasoline would be 11.5 because number of gallons of gasoline in rounded to nearest gallon.

To find mileage, we will divide number of miles by number of gallons.

The possible number of gallons of gasoline will be 12.5 gallons for 285 miles to get the minimum number of miles.

Similarly, the possible number of gallons of gasoline will be 11.5 gallons for 295 miles to get the maximum miles.

Therefore, our required range would be \frac{285}{12.5} and \frac{295}{11.5}.  

5 0
3 years ago
Trigonometry questions
trasher [3.6K]

We'll use standard labeling of right triangle ABC, C=90 degrees, legs a, b, hypotenuse c.

11.

Right triangle, cliff peak A, boat B, angle opposite cliff is B=28.9 deg. adjacent leg a=65.7 m, cliff height is leg b.

tan B = b/a

b = a tan B = 65.7 tan 28.9° = 36.3 m

12.

Similar story, boat at B, opposite b=3.5 m, rope c=12 m

sin B = b/c

B = arcsin b/c = arcsin (3.5/12) = 17.0°

13.

c=124 m, A=58°

sin A = a/c

a = c sin A = 124 sin 58 = 105.2 m

14.

That's a hypotenuse c=4-1.2 = 2.8 m to a height b=1.8m so

cos A = b/c

A = arccos b/c = arccos (1.8/2.8) = 50.0°

15.

Not a right triangle, an isosceles triangle.  Half of it is a right triangle with hypotenuse one arm, c=9.8 cm and angle opposite half the base of B=62/2=31°.  We're after d=2b:

sin B = b/c

b = c sin B

d = 2b = 2 c sin B = 2(9.8) sin 31 = 10.1 cm

Almost equilateral


4 0
4 years ago
Help with this pls!!!
Pepsi [2]
B is the answer I know because I took the test
4 0
3 years ago
As a freshman, suppose you had to take two of four lab science courses, one of two literature courses, two of three math courses
Sergeeva-Olga [200]

Answer:

We have 252 different schedules.

Step-by-step explanation:

We know that as  a freshman, suppose you had to take two of four lab science courses, one of two literature courses, two of three math courses, and one of seven physical education courses.

So from 4 lab science courses we choose 2:

C_2^4=\frac{4!}{2!(4-2)!}=6

So from 2 literature courses we choose 1:

C_1^2=\frac{2!}{1!(2-1)!}=2

So from 3 math courses we choose 2:

C_2^3=\frac{3!}{2!(3-2)!}=3\\

So from 7 physical education courses we choose 1:

C_1^7=\frac{7!}{1!(7-1)!}=7

We get: 6 · 2 · 3 · 7 = 252

We have 252 different schedules.

5 0
3 years ago
If anyone solves this question, I'll give 10pts.
tino4ka555 [31]

Answer:

9

Step-by-step explanation:

6 0
4 years ago
Read 2 more answers
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