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satela [25.4K]
3 years ago
9

Which is the best estimate for the expression? 49% of 15

Mathematics
2 answers:
docker41 [41]3 years ago
4 0
<span>49% of 15 is 7.35 
hope that helps</span>
irakobra [83]3 years ago
3 0


49%=0.49

0.49x15=7.35

49% of 15 is 7.35

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Gina looks at the architectural plan of a four-walled room in which the walls meet each other at right angles. The length of one
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Answer:

For a better understanding of the solution provided here, please find the diagram attached.

In the diagram, ABCD is the room.

AC is the diagonal whose length is 18.79 inches.

The length of wall AB is 17 inches.

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and hence, the given room is not a square.

Step-by-step explanation:

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3 regions are defined in the figure find the volume generated by rotating the given region about the specific line
anastassius [24]

The volume generated by rotating the given region R_{3} about OC is \frac{4}{g}  \pi

<h3>Washer method</h3>

Because the given region (R_{3}) has a look like a washer, we will apply the washer method to find the volume generated by rotating the given region about the specific line.

solution

We first find the value of x and y

y=2(x)^{\frac{1}{4} }

x=(\frac{y}{2} )^{4}

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\int\limits^a_b {\pi } \, (R_{o^{2} }  - R_{i^{2} } )       dy

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R_{i} = x= (\frac{y}{2}) ^{4}

a=0, b=2

v= \int\limits^2_o {\pi } \, [(\frac{y}{2})^{2} - ((\frac{y}{2}) ^{4} )^{2} )  dy

v= \pi \int\limits^2_o= [\frac{y^{2} }{4} - \frac{y^{8} }{2^{8} }}  ] dy

v= \pi [\int\limits^2_o {\frac{y^{2} }{4} } \, dy - \int\limits^2_o {\frac{y}{2^{8} } ^{8} } \, dy ]

v=\pi [\frac{1}{4} \frac{y^{3} }{3}  \int\limits^2_0 - \frac{1}{2^{8} }  \frac{y^{g} }{g} \int\limits^2_o\\v= \pi [\frac{1}{12} (2^{3} -0)-\frac{1}{2^{8}*9 } (2^{g} -0)]\\v= \pi [\frac{2}{3} -\frac{2}{g} ]\\v= \frac{4}{g} \pi

A similar question about finding the volume generated by a given region is answered here: brainly.com/question/3455095

6 0
2 years ago
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Answer:

0.09

0.16

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Step-by-step explanation:

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