The time when the maximum serum concentration is reached is obtained by equating the derivative of C(t) to 0.
i.e. dC(t)/dt = 0.06 - 2(0.0002t) = 0.06 - 0.0004t = 0
0.0004t = 0.06
t = 0.06/0.0004 = 150
Therefore, the maximum serum concentration is reached at t = 150 mins
The maximum concentration = 0.06(150) - 0.0002(150)^2 = 9 - 0.0002(22,500) = 9 - 4.5 = 4.5
Therefore, the maximum concentration is 4.5mg/L
Answer:
C) The sample does not accurately represent the population
Answer:
4/(x + 3)(x + 2)
Step-by-step explanation:
8x - 2 / (x + 3)(x - 1)(x + 2) =
4(x - 1)/(x + 3)(x - 1)(x + 2) =
4/(x + 3)(x + 2)
hope it helps
:D
Standard form is ax + by = c.
To change y+2 = 3(x-2) into that form, do:
y+2-2 = 3x -6 -2
-3x + y = -8
Which is not in the list, so none of the answers are right...
