Question

Divide 9x2 – 6x + 2 by (–1 + 3x)

Answer 1

Answer:

3 x − 1 −   1/ − 3 x + 1

Step-by-step explanation:

Answer 2

Step-by-step explanation:

The first step is to setup the division problem

$3x - 1 \sqrt{9 {x}^{2} } - 6x + 2$

Next we divide

$9 {x}^{2} \div 3x = 3x$

So now we have to multiply 3x by 3x and -1 by 3x

$3x \times 3x = 9 {x}^{2} \\ - 1 \times 3x = - 3x$

Then

$\: \: \: \: 9 {x}^{2} - 9 {x}^{2} = 0$

$- 6x + 3x = - 3x$

Now we divide

$- 3x \div 3x = - 1$

Now multiply

$- 1 \times - 1 = 1$

Now we

$- 3x + 3x = 0 \\ 2 - 1 = 1$

So the answer is

3x-1 Remains 1/3x-1

$3x - 1 + \: \frac {1}{3x - 1}$