5)

2 answers:

7 0

I would say the volume simply is Org volume times 3. there is an increase regardless of radius size. which would be a much more complicated problem

UNO [17]3 years ago

3 0

The volume increases, any factor increasing hight or radius, the volume will increase.

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a stainless steel garbage can is in the shape of a right circular cylinder. If its radius is 6 inches and its volume is 864 pi c

lubasha [3.4K]

$\bf \textit{volume of a cylinder}=v=\pi r^2 h\qquad 
\begin{cases}
r=radius\\
h=height\\
---------\\
r=6\\
v=864\pi^3
\end{cases}
\\\\\\
864\pi^3=\pi\cdot 6^2\cdot h\impliedby \textit{solve for "h"}$

5 0

3 years ago

Read 2 more answers

Compute the determinant using a cofactor expansion across the first row. Also compute the determinant by a cofactor expansion do

V125BC [204]

Answer:

Step-by-step explanation:

It is given that

$\Delta=\begin{vmatrix}3&0&3\\2 &3&3\\0 &4&-2\end{vmatrix}$

By cofactor expansion across the first row, we get

$\Delta=a_{11}C_{11}+a_{12}C_{12}+a_{13}C_{13}$

$\Delta=3\left[(-1)^{1+1}\begin{vmatrix}3&3\\4&-2\end{vmatrix}\right]+0\left[(-1)^{1+2}\begin{vmatrix}2&3\\0&-2\end{vmatrix}\right]+3\left[(-1)^{1+3}\begin{vmatrix}2&3\\0&4\end{vmatrix}\right]$

$\Delta=3\left[-18\right]+0\left[(-1)(-4)\right]+3\left[8\right]$

$\Delta=-54+0+24$

$\Delta=-30$

Therefore, the value of determinant is -30.

By cofactor expansion across the second column, we get

$\Delta=a_{12}C_{12}+a_{22}C_{22}+a_{32}C_{32}$

$\Delta=0\left[(-1)^{2+1}\begin{vmatrix}2&3\\0&-2\end{vmatrix}\right]+3\left[(-1)^{2+2}\begin{vmatrix}3&3\\0&-2\end{vmatrix}\right]+4\left[(-1)^{3+2}\begin{vmatrix}3&3\\2&3\end{vmatrix}\right]$