All categories

3 years ago

What is 43.78 in word form

Mathematics

2 answers:

KengaRu [80]3 years ago

8 0

43.78 = forty three and seventy eight hundredths.

tekilochka [14]3 years ago

3 0

Answer: Forty three and seventy ate hundredth(s)

You might be interested in

( Will hand out brainiest) A California condor left its cliff-side nest and soared downwards at a rate of 16 meters per second.

svet-max [94.6K]

First calculate the distance covered going down:

d_down = (16 m / s) * 8 s = 128 m

Then the distance going up is:

d_up = 71 m

So the distance from the ledge to the nest is:

d = 128 m – 71 m = 57 m

Therefore the elevation is:

<span>elevation = 1364 m + 57 m = 1421 m</span>

4 0

3 years ago

Keith earns $42.00 in 3 hours. How much would he earn in 10 hours? A. $135.00 B. $140.00 C. $84.00 D. $112.00

xeze [42]

The answer is B. $140

7 0

3 years ago

Read 2 more answers

What is the lowest number that can be generated using the digits 2, 8, 5, 3, 3, and 6, in any order?

wariber [46]

Answer:

233568

Step-by-step explanation:

233568

use the smallest digit on the left and write in increasing order

and the greatest digit on the right as shown.

3 0

3 years ago

Read 2 more answers

If x represents a number, then write an expression for one half the sum of x and 7.

Lostsunrise [7]

Answer:

1/2(x+7)

Step-by-step explanation:

4 0

3 years ago

(1 point) Newton's law of cooling states that the temperature of an object changes at a rate proportional to the difference betw

slavikrds [6]

Answer:

a. $\frac{dT}{dt}=k(T-Tm); T(0)=190$

b. $C_{0}=122$

c. $k=-0.00259$

d. $t=153.39838\\$ minutos

Step-by-step explanation:

a. Newton's law of cooling states that the speed with which a body is cooled is proportional to the difference between its temperature and that of the medium in which it is found. Then, the initial value problem is given by:

$Tm=68$

$\frac{dT}{dt}=k(T-Tm); T(0)=190$

b. The differential equation obtained is a differential equation of separable variables:

$\frac{dT}{T-Tm}=kdt\\\\\int {\frac{dT}{T-Tm}}=\int{kdt}\\\\Ln|T-Tm|=kt+C\\\\T(t)=C_{0}e^{kt}+Tm=C_{0}e^{kt}+68\\\\T(0)=C_{0}e^{k(0)}+68=190\\\\C_{0}=122$

c. After 33 minutes of serving the coffee has cooled to 180°:

$T(33)=122e^{33k}+68=180\\\\e^{33k}=\frac{112}{122}\\\\33k=Ln(\frac{112}{122})\\\\k=-0.00259$

$150=122e^{-0.00259t}+68\\\\Ln(\frac{150-68}{122})=-0.00259t\\\\t=153.39838\\\\$

8 0

3 years ago