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3 years ago

9

What is 15% or $48.32?

1 answer:

Alexxandr [17]3 years ago

5 0

What I got is this: 15% of $48.32 = $7.25

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Problem page the length of a rectangle is four times its width. if the perimeter of the rectangle is 70 cm , find its area.

agasfer [191]

So we can call the width of the rectangle x.
So then the length would be 4x.
The perimeter would then be 10x.
Since the perimeter is 70, we can say 70 = 10x.
And then simplify that to 7 = x.
So the length of a rectangle would be 28 cm, and the width would be 7.
So to find the area, just multiply length by width.
28*7 = 196 square cm
So the rectangle's area is 196 square cm.

I hope I helped!

5 0

3 years ago

What is 50+_that equal420

snow_lady [41]

Answer:

370

Step-by-step explanation:

50 + x = 420

x = 420 - 50

x = 370

6 0

3 years ago

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Which number is a factor of 84?

Blababa [14]

Answer:

3

Step-by-step explanation:

Factors of 84 : 1, 2, 3, 4, 6, 7, 12, 14, 21, 28, 42 and 84.

6 0

3 years ago

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If the ratio of the length of segment AC to the length of segment CB is 3:1, what is the y-coordinate of point C?

Yuki888 [10]

Answer:

The coordinates of point C are (8,8.5)

Step-by-step explanation:

The picture of the question in the attached figure

Let

$(C_x,C_y)$ ----> coordinates of point C

we have that

The horizontal distance AB is equal to

$AB_x=10-2=8\ units$

The vertical distance AB is equal to

$AB_y=10-4=6\ units$

Find the horizontal coordinate of point C

we know that

$\frac{AC}{CB}=\frac{3}{1}$

so

$\frac{AC_x}{CB_x}=\frac{3}{1}$

$AC_x=3CB_x$ ----> equation A

$AC_x+CB_x=8$ ----> equation B

substitute equation A in equation B

$3CB_x+CB_x=8$

$4CB_x=8\\CB_x=2$

$AC_x=3(2)=6$

so

The x-coordinate of point C is equal to the x-coordinate of point A plus the horizontal distance between the point A and point C

$C_x=A_x+AC_x=2+6=8$

Find the vertical coordinate of point C

we know that

$\frac{AC}{CB}=\frac{3}{1}$

so

$\frac{AC_y}{CB_y}=\frac{3}{1}$

$AC_y=3CB_y$ ----> equation A

$AC_y+CB_y=6$ ----> equation B

substitute equation A in equation B

$3CB_y+CB_y=6$

$4CB_y=6\\CB_y=1.5$

$AC_y=3(1.5)=4.5$

so

The y-coordinate of point C is equal to the y-coordinate of point A plus the vertical distance between the point A and point C

$C_y=A_y+AC_y=4+4.5=8.5$

therefore

The coordinates of point C are (8,8.5)

5 0

3 years ago

What is 4p+5=33 ? For the equation

faltersainse [42]

Answer:

p=7

Step-by-step explanation:

4p+5=33

33-5=28

4p=28

28/4=7

p=7

4(7)+5=33

28+5=33

4 0

3 years ago

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