(05.05)

Mathematics

2 answers:

Semenov [28]3 years ago

5 0

Answer:

I'm pretty sure its x is less than or equal to -7.

Step-by-step explanation:

But its definitely not y is greater than or = to -7 nor is it y is less than or equal to -7. Because that'd be on the y-axis and in the picture the line is on the x axis.

Natalka [10]3 years ago

3 0

Y greater than or equal to -7

You might be interested in

Please help!

Sindrei [870]

Answer:

D. Subtraction property of equality

B. 6.5

Step-by-step explanation:

First blank:

The equation is x + 6.5 = 13.

To solve the equation, you want x alone on the left side, showing "x = some number." Since 6.5 is being added to x, you need to SUBTRACT 6.5. You must do the same operation to both sides of an equation, so you need to SUBTRACT 6.5 from both sides of the equation. What allows you to subtract the same number from both sides of an equation is the

D. Subtraction property of equality

Second blank:

Subtract 6.5 from both sides.

x + 6.5 = 13

x + 6.5 - 6.5 = 13 - 6.5

x = 6.5

Answer: B. 6.5

4 0

3 years ago

Would appreciate the help !

aleksandr82 [10.1K]

This is one pathway to prove the identity.

Part 1

$\frac{\sin(\theta)}{1-\cos(\theta)}-\frac{1}{\tan(\theta)} = \frac{1}{\sin(\theta)}\\\\\frac{\sin(\theta)}{1-\cos(\theta)}-\cot(\theta) = \frac{1}{\sin(\theta)}\\\\\frac{\sin(\theta)}{1-\cos(\theta)}-\frac{\cos(\theta)}{\sin(\theta)} = \frac{1}{\sin(\theta)}\\\\\frac{\sin(\theta)*\sin(\theta)}{\sin(\theta)(1-\cos(\theta))}-\frac{\cos(\theta)(1-\cos(\theta))}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\$

Part 2

$\frac{\sin^2(\theta)}{\sin(\theta)(1-\cos(\theta))}-\frac{\cos(\theta)-\cos^2(\theta)}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\\frac{\sin^2(\theta)-(\cos(\theta)-\cos^2(\theta))}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\\frac{\sin^2(\theta)-\cos(\theta)+\cos^2(\theta)}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\$

Part 3

$\frac{\sin^2(\theta)+\cos^2(\theta)-\cos(\theta)}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\\frac{1-\cos(\theta)}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\\frac{1}{\sin(\theta)} = \frac{1}{\sin(\theta)} \ \ {\checkmark}\\\\$

As the steps above show, the goal is to get both sides be the same identical expression. You should only work with one side to transform it into the other. In this case, the left side transforms while the right side stays fixed the entire time. The general rule is that you should convert the more complicated expression into a simpler form.

We use other previously established or proven trig identities to work through the steps. For example, I used the pythagorean identity $\sin^2(\theta)+\cos^2(\theta) = 1$ in the second to last step. I broke the steps into three parts to hopefully make it more manageable.