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olga55 [171]
3 years ago
8

Ninety-eight percent of all babies survive delivery. However, 15 percent of all births involve Cesarean (C) sections, and when a

C section is performed, the baby survives 96 percent of the time. If a randomly chosen pregnant woman does not have a C section, what is the probability that her baby survives?
Mathematics
1 answer:
gtnhenbr [62]3 years ago
7 0

Answer:

I mean they come out of...

Step-by-step explanation:

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Please Help Me! I will give brainly!!
DerKrebs [107]

Answer:

5 1/10 meters

Step-by-step explanation:

18 4/5 can be changed to 18 8/10 so

18 8/10 - 13 7/10 = 5 1/10 meters

8 0
3 years ago
Read 2 more answers
Which like on the graph represents the equation y+4=-2x/3?
Amanda [17]

Answer:

1

Step-by-step explanation:

8 0
3 years ago
Which correctly describes the type of symmetry of the butterfly pictured?
Alexxandr [17]

I'm not 100% sure, but I think it is A - Reflectional symmetry

I think it's Reflectional symmetry because If you look at the body of the butterfly, there is an implied vertical symmetry line right through the body.

This line makes the left image look mirrored to the image on the right.

Hope this helps :))

3 0
3 years ago
Which is the solution to the inequality?
makvit [3.9K]

Answer:

b>3.133333333

Step-by-step explanation:

13/5<b-8/15

13/5+8/15<b

39+8/15<b

47/15<b

3.13333333<b

b>3.13333333

6 0
3 years ago
The sample space listing the eight simple events that are possible when a couple has three children is {bbb, bbg, bgb, bgg, gbb,
NNADVOKAT [17]

Answer:

bbbb,

bbbg, bbgb, bgbb, gbbb,

bbgg, bgbg, bggb, gbgb, gbbg, ggbb,

bggg, gbgg, ggbg, gggb,

gggg

Step-by-step explanation:

3 children: bbb, bbg, bgb, gbb, bgg, gbg, ggb, ggg

4 children: bbbb, bbbg, bbgb, bgbb, gbbb, bbgg, bgbg, bggb, gbgb, ggbb, bggg, gbgg, ggbg, gggb, gggg

You need to take a methodological approach;

The 2 easiest are the possibility of all boys and all girls;

Then consider 3 boys and 1 girl:

bbbg, bbgb, bgbb, gbbb

Then 2 boys and 2 girls:

bbgg, bgbg, bggb, gbgb, gbbg, ggbb

Lastly, 1 boy and 3 girls:

bggg, gbgg, ggbg, gggb

In total, there are 16 possibilities

P.S. interesting to note is that the number of possibilities here follows the pattern of Pascal's triangle:

       1

     1   1

   1  2  1

 1  3  3  1

1  4  6  4  1

The last row is relevant here;

There is 1 possibility where there are 4 boys;

There are 4 possibilities (in terms of the order of birth) where there are 3 boys and 1 girl;

There are 6 possibilities where there are 2 boys and 2 girls

There are 4 possibilities where there is 1 boy and 3 girls;

There is 1 possibility where there are 4 girls;

The pattern ∴ is 1 4 6 4 1, as the 5th row of Pascal's triangle reads;

If your talking about 3 children, it would match the 4th row of Pascal's triangle;

So, 1 possibility of 3 boys;

3 possibilities of 2 boys and 1 girl;

3 possibilities of 1 boy and 2 girls;

And 1 possibility of 3 girls;

If your talking about 10 children, it would match the 11th row of Pascal's triangle.

(Maths can be so cool XD)

7 0
3 years ago
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