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MatroZZZ [7]
4 years ago
7

Alice buys some inexpensive bracelets and necklaces as party favors for her jewelry showing. She pays $8 for each necklace (N) a

nd $7 for each bracelet (B). She spends less than $120. Which inequality models this situation?
A) 7B + 8N ≤ 120
B) 7B + 8N > 120
C) 7B + 8N ≥ 120
D) 7B + 8N < 120
Mathematics
2 answers:
valentinak56 [21]4 years ago
7 0

Answer: D. 7B + 8N < 120

Step-by-step explanation:

Given : Alice buys some inexpensive bracelets and necklaces as party favors for her jewelry showing.

She pays $8 for each necklace (N) and $7 for each bracelet (B).

Then , the cost of N necklaces = $8N

Cost of B bracelets = $7B

Total money spent =  Cost of N necklaces+ Cost of B bracelets

=$(8N+7B)

She spends less than $120.

i.e. $(8N+7B) < $120

Hence, the inequality models this situation :

7B + 8N < 120

ElenaW [278]4 years ago
3 0

Answer:

D: 7B+8N<120

Step-by-step explanation:

The total amount of the bracelets and necklaces is less than $120, so if you add the price of each necklace ($8) and the price of each bracelet ($7), it will be <$120.

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